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MakcuM [25]
3 years ago
15

The histograms below show the mass (in kilograms) of the offensive linemen on the University of Mount Union and the University o

f Alabama football teams. Which pieces of information can be gathered from these histogramsChoose all answers that apply:6) The linemen who play for Mount Union have more mass on average.All of the Alabama linemen have more mass than all of the Mount Union linemen.7 © None of the above

Mathematics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

Option C is correct.

None of the options is true.

Step-by-step explanation:

The histograms for the question is missing, so, it was obtained online and is attached to this solution of the question.

To check which statements are true, we first find the average using the midpoint technique.

The midpoint for each of the ranges is presented below

110 to 120 = 115

120 to 130 = 125

130 to 140 = 135

140 to 150 = 145

150 to 160 = 155

Sum of weights for Alabama linemen using the midpoint technique

= (125×4) + (135×8) + (145×4) + (155×2)

= 2470 kg

Average = (2470) ÷ (4+8+4+2)

= 137.22 kg

Sum of weights for Mount Union linemen

= (115×5) + (125×4) + (135×6) + (145×2)

= 2,175 kg

Average = (2,175) ÷ (5+4+6+2)

= 127.94 kg

So, it is evident that the average weight of Mount Union linemen isn't more than that of Alabama linemen.

Statement 2

All of the Alabama linemen have more mass than all of the Mount Union linemen

This is evidently not true because from the histogram, some linemen from Alabama have masses between 120 and 130, 130 and 140 & there are linemen from Mount Union that have masses between 130 and 140 & 140 and 150, so, it isn't right to say that all of the Alabama linemen have more mass than all of the Mount Union linemen.

So, none of the options is correct, option C.

Hope this Helps!!!

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Each exterior angle of a regular polygon is 24º.<br>How many sides does the polygon have?​
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Step-by-step explanation :

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Pls help me!!
vlada-n [284]

Answer:

<h3>Q1</h3>

The graph of y = f(x), has vertex at (1, -2)

<u>The vertex of a function f(x - 3) is going to be:</u>

  • (1 - 3, -2) = (-2, -2)
<h3>Q2</h3>
  • <em>The graph of y = f(x) has the line x = 5 as an axis of symmetry. The graph also passes through the point (8,-7). Find another point that must lie on the graph of y = f(x).</em>

The axis of symmetry is at the same distance from the symmetric points.

x = 5 is a vertical line. The point (8, -7) is 3 units to the right. So the mirror point will be 3 units to the left and have same y-coordinate: x = 5 - 3 = 2

The point is (2, -7)

<h3>Q3</h3>

The graph in blue is the translation of the red to the left by 2 units.

<u>So the equation is:</u>

  • y = f(x + 2)
<h3>Q4</h3>

y = h(x) is graphed

  • h(7) = 5
  • h(h(7)) = h(5) = -1
<h3>Q5</h3>

The graph of the function y = u(x) given

This is a odd function.

The coordinates of u(x) and u(-x) add to zero because u(-x) = -u(x)

<u>Therefore:</u>

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3 0
3 years ago
Someone pls answer this it’s so confusing lol
GenaCL600 [577]

Answer:

<h2>y = \frac{w}{h -  {2c}^{3} }</h2>

Step-by-step explanation:

w = yh - 2yc³

First of all factorize y out of the expression on the right side of the equation

That's

w = y( h - 2c³)

Next divide both sides by (h - 2c³) to make y stand alone

We have

<h3>\frac{y(h -  {2c}^{3}) }{h -  {2c}^{3} }  =  \frac{w}{h -  {2c}^{3} }</h3>

We have the final answer as

<h3>y = \frac{w}{h -  {2c}^{3} }</h3>

Hope this helps you

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