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3 years ago

Find the sum of the whole numbers from 1 to 960

Mathematics

1 answer:

agasfer [191]3 years ago

4 0

Step-by-step explanation:

A quick way to do this sort of question:

First add the last number and the first number:

1 + 960 = 961

Then divide the total amount of numbers by 2.

960 ÷2 = 480

Now multiply these two numbers together:

961 × 480 = 461280

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What is the slope of the line on the graph need answer ASAP please thank you I'm in k-12

Rina8888 [55]

The answer is -1 your welcome

3 0

2 years ago

PLEASE HELP !!!!!!!!!

iVinArrow [24]

Answer:

f (x) = 4,500 + 250x; 24 months

Step-by-step explanation:

Because 10,500 - 4,500 = 6,000

6,000 / 250 = 24

Hope this helped

4 0

3 years ago

Thank you guys so much

jeka57 [31]

Answer:

B. City P is above sea level and City R is below sea level

Step-by-step explanation:

A. City R is negative meaning it is below sea level however City Q is 0 meaning it is at sea level, so this statement is false.

C. Once again, City P is positive meaning it is above sea level but City Q is 0 meaning it is at sea level, so this statement is false.

D. Like before, City P is above sea level and City Q is at sea level not below, so this is, once again, false.

6 0

3 years ago

Write the equation of a line that is parallel to the line 2x - 3y = 5 and passes through the point (2, -1)

jek_recluse [69]

Answer:

The equation of the line is 2x - 3y = 7 ⇒ answer A

Step-by-step explanation:

* Lets revise the relation between the parallel lines

- If two lines are equal then their slopes are equal

- We can make an equation of a line by using its slope and

a point on the line

- If the slope of the line is m and passing through the point (x1 , y1),

then we can use this form [y - y1]/[x - x1] = m to find the equation

* Lets solve the problem

- The line is parallel to the line 2x - 3y = 5

∴ the slope of the line = the slope of the line 2x - 3y = 5

- Rearrange the terms of the equation to be in the form

y = mx + c to find the slope of it

∵ 2x - 3y = 5 ⇒ subtract 2x from both sides

∴ -3y = 5 - 2x ⇒ divide two sides by -3

∴ y = 5/-3 - 2x/-3 ⇒ y = 2/3 x - 5/3

∴ The slop of the line is 2/3

∵ The line passes through point (2 , -1)

* Lets use the rule to find the equation of the line

∵ y - (-1)/x - 2 = 2/3

∴ y + 1/x - 2 = 2/3 ⇒ by using cross multiplication

∴ 3(y + 1) = 2(x - 2) ⇒ open the brackets

∴ 3y + 3 = 2x - 4 ⇒ put x an d y in one side

∴ 2x - 3y = 3 + 4

∴ 2x - 3y = 7

* The equation of the line is 2x - 3y = 7

8 0

3 years ago

You have a large jar that initially contains 30 red marbles and 20 blue marbles. We also have a large supply of extra marbles of

Dima020 [189]

Answer:

There is a 57.68% probability that this last marble is red.

There is a 20.78% probability that we actually drew the same marble all four times.

Step-by-step explanation:

Initially, there are 50 marbles, of which:

30 are red

20 are blue

Any time a red marble is drawn:

The marble is placed back, and another three red marbles are added

Any time a blue marble is drawn

The marble is placed back, and another five blue marbles are added.

The first three marbles can have the following combinations:

R - R - R

R - R - B

R - B - R

R - B - B

B - R - R

B - R - B

B - B - R

B - B - B

Now, for each case, we have to find the probability that the last marble is red. So

$P = P_{1} + P_{2} + P_{3} + P_{4} + P_{5} + P_{6} + P_{7} + P_{8}$

$P_{1}$ is the probability that we go R - R - R - R

There are 50 marbles, of which 30 are red. So, the probability of the first marble sorted being red is $\frac{30}{50} = \frac{3}{5}$ .

Now the red marble is returned to the bag, and another 3 red marbles are added.

Now there are 53 marbles, of which 33 are red. So, when the first marble sorted is red, the probability that the second is also red is $\frac{33}{53}$

Again, the red marble is returned to the bag, and another 3 red marbles are added

Now there are 56 marbles, of which 36 are red. So, in this sequence, the probability of the third marble sorted being red is $\frac{36}{56}$

Again, the red marble sorted is returned, and another 3 are added.

Now there are 59 marbles, of which 39 are red. So, in this sequence, the probability of the fourth marble sorted being red is $\frac{39}{59}$ . So

$P_{1} = \frac{3}{5}*\frac{33}{53}*\frac{36}{56}*\frac{39}{59} = \frac{138996}{875560} = 0.1588$

$P_{2}$ is the probability that we go R - R - B - R

$P_{2} = \frac{3}{5}*\frac{33}{53}*\frac{20}{56}*\frac{36}{61} = \frac{71280}{905240} = 0.0788$

$P_{3}$ is the probability that we go R - B - R - R

$P_{3} = \frac{3}{5}*\frac{20}{53}*\frac{33}{58}*\frac{36}{61} = \frac{71280}{937570} = 0.076$

$P_{4}$ is the probability that we go R - B - B - R

$P_{4} = \frac{3}{5}*\frac{20}{53}*\frac{25}{58}*\frac{33}{63} = \frac{49500}{968310} = 0.0511$

$P_{5}$ is the probability that we go B - R - R - R

$P_{5} = \frac{2}{5}*\frac{30}{55}*\frac{33}{58}*\frac{36}{61} = \frac{71280}{972950} = 0.0733$

$P_{6}$ is the probability that we go B - R - B - R

$P_{6} = \frac{2}{5}*\frac{30}{55}*\frac{25}{58}*\frac{33}{63} = \frac{49500}{1004850} = 0.0493$

$P_{7}$ is the probability that we go B - B - R - R

$P_{7} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{33}{63} = \frac{825}{17325} = 0.0476$

$P_{8}$ is the probability that we go B - B - B - R

$P_{8} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{30}{65} = \frac{750}{17875} = 0.0419$

So, the probability that this last marble is red is:

$P = P_{1} + P_{2} + P_{3} + P_{4} + P_{5} + P_{6} + P_{7} + P_{8} = 0.1588 + 0.0788 + 0.076 + 0.0511 + 0.0733 + 0.0493 + 0.0476 + 0.0419 = 0.5768$

There is a 57.68% probability that this last marble is red.

What's the probability that we actually drew the same marble all four times?

$P = P_{1} + P_{2}$

$P_{1}$ is the probability that we go R-R-R-R. It is the same $P_{1}$ from the previous item(the last marble being red). So $P_{1} = 0.1588$

$P_{2}$ is the probability that we go B-B-B-B. It is almost the same as $P_{8}$ in the previous exercise. The lone difference is that for the last marble we want it to be blue. There are 65 marbles, 35 of which are blue.

$P_{2} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{35}{65} = \frac{875}{17875} = 0.0490$

$P = P_{1} + P_{2} = 0.1588 + 0.0490 = 0.2078$

There is a 20.78% probability that we actually drew the same marble all four times

3 0

3 years ago