I believe this is an inequality because this doesn’t pass the origin point 0
Does not pass 0,0
If I’m wrong so sorry
Solution:
As, You have Written Polygon ABCD is a rectangle.
It is a Four sided Polygon , having all it's interior angles equal to 90°.As well as Opposite sides are equal(AB=CD,AD=BC), equal diagonals(AC=B D).
Join any of the diagonal of Rectangle either AC or B D.
In Right Δ ABC , Right angled at B
---(1)
In Right Δ ADC , Right angled at D
---(2)
Adding (1) and (2) that is LHS to LHS and RHS to RHS
Ar( Δ ABC) +Ar( Δ ADC)![=\frac{1}{2}\times[ AB \times BC+ AD \times DC]\\\\=\frac{1}{2}[2 \times AB \times BC][\text{As, AB=CD, and BC=AD}]\\\\ = AB \times BC](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%5B%20AB%20%5Ctimes%20BC%2B%20AD%20%5Ctimes%20DC%5D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%5B2%20%5Ctimes%20AB%20%5Ctimes%20BC%5D%5B%5Ctext%7BAs%2C%20AB%3DCD%2C%20and%20BC%3DAD%7D%5D%5C%5C%5C%5C%20%3D%20AB%20%5Ctimes%20BC)
So, Area of Rectangle= Product of any two Adjacent Sides
8 - {x - (5 + x)}
= 8 - {x - 5 - x}
= 8 + 5
= 13
Answer:
QS = 38
Step-by-step explanation:
First, we need to find the value of x.
Given that R is the midpoint of Q and S, that means QR = RS.
6x-11 = 2x+9
Solve.
x = 5.
To find QS, we need to solve the following equation:
6x-11 + 2x+9
Substitute 5 for x.
6(5)-11+2(5)+9
30-11+10+9
38
Get n by itself in both inequalities
(This program doesn't allow for regular less than or greater than signs, so for the purposes of this problem I will be using less than or equal to (≤) and greater than or equal to (≥) signs)
Inequality 1:

Inequality 2:

Now that you have both of the n's by themselves, you can put the two inequalities together, like this

Just keep in mind that these are supposed to be regular less than signs