Someone help me with this question please!!!!

Mathematics

1 answer:

Sindrei [870]3 years ago

4 0

Answer:

a) 1/(7x-14) b) 2(36-y^2)

a) 8/27 b) a = -3 b= 5/2 c= -1/2

Step-by-step explanation:

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Mars2501 [29]

Answer:

$186.86

Step-by-step explanation:

4 eggs cost:

1 dollar per dozen (12 eggs), so by unitary method (ratios), we can find cost of 4 eggs. Shown below:

$\frac{1}{12}=\frac{x}{4}\\12x=4\\x=0.33$

So, 4 eggs cost $0.33 approx

12 lb. flour cost:

2.50 dollar per pound, so 12 pounds would simply cost:

2.5 * 12 = $30

14 lb of sugar cost:

4.50 dollar per pound means 14 pounds would cost:

4.5 * 14 = $63

2 ready-made edible flowers cost:

5 cents for each flower means 2 flowers would cost:

5 cent = 0.05 dollars

0.05 * 2 = $0.10

We add all up to find cost of 1 cake. Shown below:

Cost of 1 cake = $0.33 + $30 + $63 + $0.10 = $93.43

Cost of 2 cakes = $93.43 * 2 = $186.86

8 0

3 years ago

PLEASE HELP!!!!!!!!!!!!! DUE SOON

Sergio039 [100]

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t$

now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+65}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{65}{2(-16)}~~,~~0-\cfrac{65^2}{4(-16)} \right) \implies \left( \cfrac{65}{32}~,~0- \cfrac{4225}{-64}\right)$

$\bf \left( \cfrac{65}{32}~,~0+ \cfrac{4225}{64}\right)\implies \left( \stackrel{seconds}{2\frac{1}{32}}~~,~~ \stackrel{feet~hight}{66\frac{1}{64}}\right)$