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cestrela7 [59]
3 years ago
9

How do I add mixed numbers8 1/2 +1/6​

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
6 0

Answer:

<u><em>26/3  is your answer as a improper fraction </em></u>

<u><em>8.6 is your answer as a decimal </em></u>

<u><em>8 2/3 is your answer as a mixed number </em></u>

How to add mixed numbers Step-by-step:

1) find the least common denominator

2) find the equivalent fractions  

3) add the the fractions, add the whole numbers

4) write your answer in lowest terms

pentagon [3]3 years ago
5 0

Answer:

26/3

Step-by-step explanation:

8½ + 1/6

= 17/2 + 1/6

= 102 + 2/12

= 104/12

= 26/3

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Lemur [1.5K]

Answer:

4/5 to the 5th power

Step-by-step explanation:

4 0
3 years ago
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Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1
Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(c) 0.0039

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

P(x=r)=^nC_rp^rq^{n-r}

(a) Exactly two will be drunken drivers.

P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}

P(x=2)=66(0.2)^{2}(0.8)^{10}

P(x=2)=\approx 0.28347

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)

P(x=3\text{ or }x=4)=P(x=3)+P(x=4)

Using binomial we get

P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}

P(x=3\text{ or }x=4)=0.236223+0.132876

P(x=3\text{ or }x=4)\approx 0.369099

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

P(x\geq 7)=1-P(x

P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]

P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]

P(x\leq 7)=1-[0.9961]

P(x\leq 7)=0.0039

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)

P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315

P(x\leq 5)=0.9806

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

5 0
3 years ago
An online camping gear company ships two camping tents to a customer. Each tent weighs 6 lb 10 oz,. What is their combined weigh
dezoksy [38]
<em>The answer is 13 pounds (lbs.) and 4 ounces (oz.). There are 2 tents and each is 6 pounds. Add those together and that is 12 pounds. All that is left is to add the ounces. 10+10=20. Since there are only 16 ounces in a pound and we have 20 ounces, we add an extra pound and are left with 4 ounces. </em>
5 0
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Convert these decimal into a fraction 0.457, 0.797, 0.815, and 0.242
kogti [31]
.457/100 .797/100 .815/100 .242/100
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3 years ago
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lilavasa [31]

Answer:

384

Step-by-step explanation:

All you have to do is multiply the three numbers

5 0
3 years ago
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