4(73)+3
273+3
276
Because you have to subsititue 73 for x. So you have to multiply 73 by 4 then what you get out of that you have to add it by 3.
37 x 10 = 370
21 x 11 = 231
Mark worked 21 Hours, Jack worked 37 Hours.
Percy solved the equation by expanding the expression on the left-hand side, and this is incorrect
<h3>How to determine the true solution?</h3>
The equation is given as:
x^2 + 7x + 12 = 12
The first step in solving the equation is to equate the equation to 0.
i.e.
x^2 + 7x + 12 - 12 = 0
This given
x^2 + 7x = 0
From the question, Percy solved the equation by expanding the expression on the left-hand side
Hence, Percy's solution is incorrect
Read more about equations at:
brainly.com/question/2972832
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Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
