The curve given has asymptotes at x=0 and y=0. We wish to move it right 7 units so the asymptote becomes x=7 and down 5 so the asymptote is y=-5
To move a function down 5 units subtract 5 from it. To move it right we subtract 7 from the independent variable (from the x). The new function is y=(3/(x-7))-5
y= (3 over (x-7)) then minus 5
You have to make a tape diagram and divide it in to 9 parts because it is 5 out of 9 then you will make a bracket pointing to only 4 parts of the tape diagram then you do 36/9 and it will equal 4 so put 4 in to each part and so 4 x 4 is 16 so the answer is 16 people prefer historical books
Step-by-step explanation:
Hey there!
The amount deposited= $1800
And it's just 20% of total monthly amount.
Let total amount be "x".
Then;
$1800 = 20% of X

or, 180000= 20x
or, X = 180000=/20
Therefore, total monthly amount or income was $9000.
<u>Hope </u><u>it </u><u>helps!</u>
First, make it into slope intercept form. Subtract x form both sides
x (-x) - y = 5 (-x)
-y = -x + 5
Isolate the y. Divide -1 from both sides
(-y)/-1 = (-x + 5)/-1
y = x - 5
The slope in the form: y = mx + b, is m, which is next to the x
In this case, the m is 1
You're slope is 1
hope this helps
The equation of the perpendicular bisector of BC with B(-2, 1), and C(4, 2) is y = 7.6 - 6•x
<h3>Which method can be used to find the equation of the perpendicular bisector?</h3>
The slope, <em>m</em>, of the line BC is calculated as follows;
- m = (2 - 1)/(4 - (-2)) = 1/6
The slope of the perpendicular line to BC is -1/(1/6) = -6
The midpoint of the line BC is found as follows;

The perpendicular bisector is the perpendicular line constructed from the midpoint of BC.
The equation of the perpendicular bisector in point and slope form is therefore;
(y - 1.5) = -6•(x - 1)
y - 1.6 = -6•x + 6
y = -6•x + 6 + 1.6 = 7.6 - 6•x
Which gives;
Learn more about equations of perpendicular lines here:
brainly.com/question/11635157
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