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3 years ago

Needing some help please

Mathematics

1 answer:

notka56 [123]3 years ago

6 0

Answer: Should be (4,0)

Step-by-step explanation:

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Calculate the difference scores for the following data from a repeated measures study. Conduct a repeated measures t-test at apl

Delicious77 [7]

Answer:

There is no difference as per statistical evidence.

Step-by-step explanation:

We calculate t statistic from the formula

t =difference in means/Std error of difference

Here n1 = n2

t = (x bar - y bar)/sq rt of s1^2+s2^2

Let treatment I =X = 34 41 38 29

Treatment II Y = 39 48 35 36

X Y

Mean 35.50 39.50

Variance 81.00 105.00

H0: x bar = y bar

Ha: x bar not equal to y bar

(Two tailed test at 0.05 significant level)

N1 = 4 and N2 = 4

df=N1+N2-2 = 6

s1^2 = 81/3 =27 and s2^2 = 105/3 = 35

Std error for difference =

t = -1.02

p =0.348834

p>0.05

Since p value >alpha we accept null hypothesis.

Hence there is statistical evidence to show that there is no difference in the mean level of scores.

6 0

3 years ago

Using only the numbers 4 through 12, fill in the circles so that the numbers on each straight line add up to 21

dangina [55]

Answer:

This was fun if you have anymore of these feel free to message me on here if you need help

3 0

3 years ago

The pinata weighs 11/4 pounds without candy.He adds 8bags that weighs 3/8,3/8,1/2,1/2,1/2,3/4,3,11/4 how much will the pinata we

Natalka [10]

Answer:

$Weight = \frac{23}{2}$

Step-by-step explanation:

Given

Weight of Pinata = 11/4 lb

Weight of candies = 3/8, 3/8, 1/2 , 1/2, 1/2, 3/4, 3, 11/4

Required

Weight of Pinata when filled with candies

To solve this question, we simply need to add all weights together

First, we need to add up the weight of the candies

$Candies = \frac{3}{8} + \frac{3}{8} + \frac{1}{2}+ \frac{1}{2}+ \frac{1}{2}+ \frac{3}{4} + 3 + \frac{11}{4}$

Take LCM

$Candies = \frac{3 + 3 + 4 +4 + 4 + 6 + 24 + 22}{8}$

$Candies = \frac{70}{8}$

Simplify:

$Candies = \frac{35}{4}$

Next; Add the weight of the candies to the weight of pinata

$Weight = Candies + Pinata$

$Weight = \frac{35}{4} + \frac{11}{4}$

Take LCM

$Weight = \frac{35 + 11}{4}$

$Weight = \frac{46}{4}$

Simplify

$Weight = \frac{23}{2}$

<em>Hence, the weight of the Pinata after it is filled with candies is 23/2 lb</em>

4 0

4 years ago

-6x + 3x = -21 linear equations

snow_tiger [21]

well combine like terms

-3x = -21

divide both sides by -3

x = 7

8 0

3 years ago

Read 2 more answers

It costs $2.80 to make a sandwich at the local deli shop. To make a profit, the deli sells it at a price that is 170% of the cos

Svetlanka [38]

Answer:

Sandwich sells for $4.76 .

Step-by-step explanation:

As given

It costs $2.80 to make a sandwich at the local deli shop.

To make a profit, the deli sells it at a price that is 170% of the cost.

170% is written in the decimal form

$= \frac{170}{100}$

= 1.7

Thus

Sandwich selling cost = 1.7 × Cost of making

Put all the values in the above

Sandwich selling cost = 1.7 × $ 2.80

= $4.76

Therefore the Sandwich sells for $4.76 .

7 0

3 years ago

Read 2 more answers