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Nikitich [7]
2 years ago
12

I am thinking of six different odd numbers, the mean of the numbers is 16, the median is 15, the range is 26, the greatest numbe

r is 31, what is the greatest number value for the 2nd number?
Mathematics
1 answer:
Sedaia [141]2 years ago
4 0

Answer:

Step-by-step explanation:

information from the range

If the range is 26 and the largest number is 31 then the smallest number is 31 - 26  = 5

Information from the median

The median must consist of 2 numbers because we have 6 integers for the data and median must consist of the middle 2. Since we are told that the median is 15 and we need 2 integers the other integer must  be 15 as well..

So what do we know so far.

5      15 15         31

Information from the mean

There are six integers making up the series of numbers. The mean is 16. Therefore all 6 integers added together must be 6 * 16 = 96

What do we have so for?

5 + 15 + 15 + 31 = 66

What do the other two numbers sum to?

96 -66 = 30

Getting the answer.

The first number to try must be 13. It has to be below 15 (the median and odd. That's 13).

So now we have

5 13 15 15 ___ 31

But from the mean we need 30

30 - 13 = 17

And we have a winner because 17 is above 15.

Answer

5 13 15 15 17 31

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