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3 years ago

in the cell, part of the Golgi appartus will pinch off and move away. what is the function of this process?

2 answers:

6 0

Parts of the golgi apparatus break off into transport vesicles. These vesicles are especially important after protein synthesis when finished products of proteins need to be transported elsewhere within the cell's membrane or outside the cell.

Olenka [21]3 years ago

3 0

Answer:

To deliver proteins to other locations in the cell

Explanation:

Once the Golgi body packages and sorts proteins, it forms vesicles that can carry the modified proteins to other parts of the cell.

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Alex_Xolod [135]

The first one the boxes Balanced
in the second one the box would move to the right

5 0

3 years ago

Genetics experiments on the breeding of plants or animals are based on the laws of _____.

ra1l [238]

The answer is D (probability)

4 0

3 years ago

Describe the process that maintained a stable tasmanian devil population size before the appearance of dftd in 1996.

Vinvika [58]

Answer:

Prior to the appearance of DFTD, it was genetic variation and gene flow that were maintaining the population. Having more genetic variation and movement of genes between populations of Tasmanian Devils likely allowed them to avoid an inbreeding depression.

Explanation:

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2 years ago

Cross a parent that is homozygous recessive for both traits (bbee) with a dihybrid (BbEe). First, draw a Punnett square in your

Bas_tet [7]

In this question, one parent is homozygous recessive (bbee) and other parent is dihybrid (BbEe)
B - black fur dominant trait
b - white fur recessive
E- black eyes dominant
e - red eyes recessive

a punnett square shows all the possible combinations of genotypes with the corresponding phenotypes that the offspring could inherit.
the genotypes and their phenotypes for the offspring are given below ;
BBEE / BbEe / BbEE / BBEe - black fur and black eyes
Bbee / BBee - black fur and red eyes
bbee - white fur and red eyes
bbEe / bbEE - white fur and black eyes

after analysing the punnett square the following results are obtained;
black fur and black eyes - BbEe- 4/16
black fur and red eyes -Bbee - 4/16
white fur and black eyes - bbEe - 4/16
white fur and red eyes -bbee - 4/16

6 0

3 years ago

Read 2 more answers

This tutorial will take you step by step through the question. Individuals with the genotypes Aa Bb CC Dd and Aa bb Cc Dd are cr

Mrac [35]

Answer:

The correct answer is -

a) 1/16

b) 1/64

c) 1/32

Explanation:

According to the law of independent assortment, each allele of a particular gene has equal chances of getting inherited into the gametes.

In a Mendelian cross of Aa x Aa would give;

AA = 1/4,

Aa = 2/4 and

aa = 1/4

The result of the cross between AaBb x AaBb would be 1/16 due to the fact that probability is still the same AA = 1/4, BB = 1/4 therefore, AABB = 1/16 = 1/4× 1/4.

Now based on this crossing the following:

AaBbCCDd x AabbCcDd.

Take each allele as individual

Aa x Aa would give; AA = 1/4, Aa = 2/4 and aa = 1/4

Bb x bb would give; BB = 1/2, bb = 1/2

CC x Cc would give; CC = 1/2, Cc = 1/2

Dd x Dd would give; DD = 1/4, Dd = 2/4 and dd = 1/4

Then the probability of progeny of the following would be:

a) the probability of AaBbCcDd = 2/4 x 1/2 x 1/2 x 2/4 = 1/16

b) the probability of aabbCCdd = 1/4 x 1/2 x 1/2 x 1/4 = 1/64

c) the probability of AabbCcDD = 2/4 x 1/2 x 1/2 x 1/4 = 1/32

6 0

3 years ago