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2 years ago

How to solve this problem

Mathematics

1 answer:

I am Lyosha [343]2 years ago

3 0

What problem? I don't see amything

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Is 2/3 greater than 2/5?

svetoff [14.1K]

Yes. 2/3 is greater than 2/5. You can check this by cross multiplication or easier just look at the denominator and numerator. In this case the numerator is the same so it's easier in a sense that you need to look at the denominator. Since the denominator 3 is close to the numerator 2 it shows that it's almost a whole unlike the other fraction. You can also convert each fraction to decimals and compare it which is also easy. Just divide the numerator by the denominator and you've got a decimal. Hope this helps!

7 0

3 years ago

Which of the following is equivalent to 7-2(x+2) < 4-3(1 - x)?

iren [92.7K]

Answer:

-x<-16

Step-by-step explanation:

4-3(1-x)

x=-1

7-2(x+2)

x=2

5 0

3 years ago

Use the given map to find the coordinates of a point that lies on the directed line segment from c to d and partitions the segme

Lelechka [254]

Given:

The line segment is passing through the points (-9,-3) and (8,5),

Divide the segment in the ratio of 1:4.

Use the formula,

$\begin{gathered} (\frac{mx_2+nx_1}{m+n},\frac{my_2-ny_1}{m+n}) \\ (x_1,y_1)=(-9,-3) \\ (x_2,y_2)=(8,5) \\ m\colon n=1\colon4 \end{gathered}$

It gives,

$\begin{gathered} (\frac{1(8)+4(-9)}{1+4},\frac{1(5)+4(-3)}{1+4}) \\ (-\frac{28}{5},-\frac{7}{5}) \end{gathered}$

Answer:

$(-\frac{28}{5},-\frac{7}{5})$

8 0

10 months ago

A farmer wants to fence in a rectangular field that encloses 3600 square feet. One side of the field is along a river and does n

andriy [413]

Answer:

C(x) = $\$3.50(\frac{x^2+7200}{x})$

Step-by-step explanation:

Data provided in the question:

Area of the field = 3600 square feet

Fencing charges = $3.50 per foot

Let the side along the river be 'x' feet and the other side of the 'B'

now,

Area of rectangle = Bx = 3600 square feet

B = $\frac{3600}{x}$ feet

and total length to be fenced = x + 2B

therefore,

Total cost of fencing = Fencing charges × total length to be fenced

Total cost of fencing = $3.50 × ( x + 2B )

substituting the value of B from (1)

Total cost of fencing, C(x) = $\$3.50(x+2\times\frac{3600}{x})$

C(x) = $\$3.50(\frac{x^2+7200}{x})$

4 0

3 years ago

The lenght of a rectangle is 4 cm less than three times the width. the perimeter is 64 cm

dybincka [34]

Let the width be x cm.
Then length=3x-4 cm.
Its perimeter is 64 cm.
We know that perimeter of a rectangle= 2(length+width)
So,
2(3x-4+x)=64
6x-8+2x=64
6x+2x=64+8
8x=72
x=9
Therefore,
length=(3×9-4)cm=(27-4)cm=23 cm.
Width=9 cm.

5 0

2 years ago

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