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3 years ago

Identify the area of the rhombus. HELP PLEASE!!

Mathematics

1 answer:

Zinaida [17]3 years ago

7 0

Answer:

A = (x^2 - 2x - 8) m^2

Second option

Step-by-step explanation:

Area of rhombus = 1/2 d1 * d2

= 1/2(2x+4)(x-4)

= 1/2 (2x^2 -8x + 4x - 16)

= 1/2 (2x^2 - 4x - 16)

= x^2 - 2x - 8

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3 years ago

Which equation demonstrates the additive identity property?

Bezzdna [24]

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Step-by-step explanation:

Solve for o in the equation (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 41o(7 + 4)(1) = 7 + 41o(7 + 41) + ( - 7 - 41) = 0

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Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o(1) = 7 + 287o + 1681o + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 164o(1): Distribute the 164o to each term in (1)

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Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o = 7 + 287o + 1681o + ( - 7 - 41) = 0

Step 1: Group variables: We need to group our variables (7 and 14©(7. To do that, we subtract 14©(7 from both sides (7 - 14©(7 = 14©(7 - 14©(7

0o 0 = 0 0 o =

5 0

3 years ago

Read 2 more answers

(3x – 1) : (x - 2) = x – 2x (x—4)<br> срочно, сор.

RSB [31]

$\frac{3x-1}{x-2}=x-2x(x-4) \frac{3x-1}{x-2}=x-2x^{2} +8x \\\frac{3x-1}{x-2}=-2x^{2} +9x3x-1= (-2x^{2} +9x)(x-2)\\3x-1= -2x^3+4x^{2} +9x^{2} -18x\\3x-1=-2x^3+13x^{2} -18x\\2x^3 -13x^{2} +18x+3x -1=0\\2x^3 -13x^{2}+21x-1=0\\ x =0.05 /or/x=3.7$

ok done. Thank to me :>

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3 years ago