Answer:
The length of the segment F'G' is 7.
Step-by-step explanation:
From Linear Algebra we define reflection across the y-axis as follows:
, 
(Eq. 1)
In addition, we get this translation formula from the statement of the problem:
, 
(Eq. 2)
Where:
- Original point, dimensionless.
- Transformed point, dimensionless.
If we know that 
and 
, then we proceed to make all needed operations:
Translation
Reflection
Lastly, we calculate the length of the segment F'G' by Pythagorean Theorem:
![F'G' = \sqrt{(5-5)^{2}+[(-1)-6]^{2}}](https://tex.z-dn.net/?f=F%27G%27%20%3D%20%5Csqrt%7B%285-5%29%5E%7B2%7D%2B%5B%28-1%29-6%5D%5E%7B2%7D%7D)
The length of the segment F'G' is 7.
Answer:
kelly
Step-by-step explanation:
51 meters is longer
If you add the numbers 57 and 59 together you get 116
You have to add up the numbers to equal 39....so it's 18+12+9=39
Answer:
joint variation means L (safe load) is directly proportional to both w and d2
inverse proportionality means L = k/l
So the equation is:
L = k(wd2/l)
You are given:
w = 6 in
d = 5 in
l = 12 ft
L = 7666 lbs
7666 = k(6*52/12)
Solve for the constant, k.
7666 = k (6*25/12)
7666 = k (150/12)
7666 = k (12.5)
613.28 lbs/(ft.in3) = k
Use this k-value to solve for L in the last part of the question.
What safe load, L would a beam 3 in. wide, 7 in. deep and 15 ft long of the same material support? (Round off your answer to the nearest pound.)
w = 3 in
d =7 in
l = 15 ft
k = 613.28 lbs/(ft.in3)
Final Safe load = 6010.144 lbs *** Edited for clarity and to fix a multiplication erro
