Answer:
f the equation is in the form, ax + b = c, where x is the variable, you can solve the equation as before. First “undo” the addition and subtraction, and then “undo” the multiplication and division. Solve 3y + 2 = 11. Subtract 2 from both sides of the equation to get the term with the variable by itself.
Step-by-step explanation:
Using function concepts, it is found that the turning points of the graph are:
- November 2000, when it goes from increasing to decreasing.
- December 2000, when it goes from decreasing to increasing.
- June 2001, when it goes from increasing to decreasing.
In a graph:
- A function is increasing if it is <u>pointing upwards.</u>
- If it is <u>pointing downwards,</u> it is decreasing.
- A turning point is when the function changes from <u>decreasing to increasing or vice-versa</u>.
In this problem:
- Initially, the function is increasing.
- In month 3, that is, November 2000, it starts to decrease, thus, in November 2000, we have a<u> turning point.</u>
- The next month, that is, December 2000, it starts to increase again, so it is another <u>turning point</u>.
- It increases until month 9, which is June 2001, when it starts to decrease, being the <u>final turning point.</u>
A similar problem is given at brainly.com/question/13539822
formula for volume = V=PI x r^2 x H so replace letters with known values and work the problem out
215 in.^3 = 3.14 x r^2 x 7.5
215/(7.5x3.14) = r^2/(7.5 x 3.14)
r^2 = (215/7.5x3.14)
r^2 = 9.1295
Now, taking the square root of both sides, we get:
sqrt(r^2) = r
sqrt(9.1295) = 3.021
r = 3 inches
Answer: The total number of logs in the pile is 6.
Step-by-step explanation: Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two logs.
We are to find the total number of logs in the pile.
Let n represents the total number of logs in the pile.
Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with
first term, a = 32 and common difference, d = -6.
We know that
the n-th term of an arithmetic sequence with first term a and common difference d is
Since there are n logs in the pile, so we get
Thus, the total number of logs in the pile is 6.
The order of operations is PEMDAS. You would work on multiplying the -6 and 3.
