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prisoha [69]
2 years ago
8

What is the midpoint of the segment shown below

Mathematics
1 answer:
Softa [21]2 years ago
6 0

Answer:

(-1, -1/2)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates and divide by 2

( -11+9)/2 = -2/2 = -1

To find the y coordinate of the midpoint, add the y coordinates and divide by 2

(0+-1)/2 = -1/2

(-1, -1/2)

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the answer is D

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If you take wha it says and plug it in, it makes the most sense

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In the figure below, ∆ABC ~ ∆QRS.
sergiy2304 [10]

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QR/AB=QR/50=1/10

QR=5

SO THAT TRIANGLE ABC IS EQUAL TO TRIANGLE QRS(2SIDES PROPORTIONAL.INC. ANGLE)

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777dan777 [17]

Answer:

Step-by-step explanation:

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6 0
2 years ago
Simplify (8^4/10^4)^-1/4using rational exponents
Vlad1618 [11]

Answer:

   (\frac{8^4}{10^4} )^{-\frac{1}{4} }  = \frac{5}{4}

Step-by-step explanation:

<u><em>Explanation</em></u>

Given  

       (\frac{8^4}{10^4} )^{-\frac{1}{4} }

By using algebra formulas

  (\frac{a}{b} )^{m} = \frac{a^m}{b^n}

(\frac{8^4}{10^4} )^{-\frac{1}{4} } = \frac{(8^{4})^{\frac{-1}{4} }  }{(10^{4} )^{\frac{-1}{4} } }

(a^{m} )^{n} = a^{mn}

\frac{(8^{4})^{\frac{-1}{4} }  }{(10^{4} )^{\frac{-1}{4} } } = \frac{8^{4X\frac{-1}{4} } }{10^{4 X\frac{-1}{4} } }

          = \frac{8^{-1} }{10^{-1} }

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<u><em>Final answer:-</em></u>

 (\frac{8^4}{10^4} )^{-\frac{1}{4} }  = \frac{5}{4}

7 0
3 years ago
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