Answer:do it correct and do your best please yourself do what is right let every body know this is ak200342 talking to you.
Explanation:keep your head up.
Falling for 1 second it would have accelerated to 9.8 metres per second
so the answer is 9.8*0.05=0.49m/sec
that is your answer
In Newton's cannonball experiment, if the velocity is equal to the orbital velocity then the cannonball will stay in Orbit.
Newtons cannonball experiment stated that the distance that a cannonball will travel, before being drawn into the Earth by the forces of gravity, is dependent on the initial velocity.
Therefore, if the cannonball is launched at a velocity that matches the orbital velocity, then it will not be able to be drawn in by gravity due to the Earth moving away from the cannonball at the same speed at which the cannonball itself is falling.
This means that the cannonball will continue to fall without reaching the Earth, therefore staying in orbit, much like that of the moon or planets around the sun.
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1.41 × 10³⁰ MeV
As we know, E=mc², where E is energy, m is mass and c is the speed of light(i.e. 3×10⁸ m/s).
Given mass = 2.5 kgs
∴ E = (2.5)×(3×10⁸)² J = 22.5×10¹⁶ J
As our answer is in joules so we have to convert it into mega electron volt(MeV)
1 J = 6.242 × 10¹² MeV
⇒ 22.5×10¹⁶ J = 22.5×10¹⁶ × (6.242 × 10¹²) MeV
⇒1.41 × 10³⁰ MeV
If you want to learn more about mass-energy conversions then you can check out this link:
https://brainly.in/question/9760064
