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When you double capacitance and inductance, the new resonance frequency becomes f/2.
- Resonance frequency:
The resonance frequency of RLC series circuit, is the frequency at which the capacity reactance is equal to inductive reactance.
It can also be defined as the natural frequency of an object where it tends to vibrate at a higher amplitude.
Xc = Xl
which gives the value for resonance frequency:
where;
f is the resonance frequency
L is the inductance
C is the capacitance
When you double capacitance and inductance, the new resonance frequency becomes;
Thus from above,
When you double capacitance and inductance, the new resonance frequency becomes f/2.
Learn more about resonance frequency here:
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<u>Answer:</u>
a) Minimum speed must he drive off the horizontal ramp = 39.78 m/s
b) Minimum speed must he drive off the horizontal ramp with 7° above the horizontal = 23.93 m/s
<u>Explanation:</u>
a) The height of ramp = 1.5 meter
Horizontal distance he must clear = 22 meter
The car is having horizontal motion and vertical motion. In case of vertical motion the acceleration on the car is acceleration due to gravity.
We have equation of motion, , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
In case of vertical motion initial velocity = 0 m/s, acceleration = 9.8 , we need to calculate time when displacement = 1.5 meter.
So the car has to cover a distance of 22 meter in 2.119 seconds.
So minimum speed required = 22/0.553 = 39.78 m/s
Minimum speed must he drive off the horizontal ramp = 39.78 m/s
b) When the take of angle is 7⁰ the vertical speed of car is not zero = V sin 7 = 0.122 V
So the in case of vertical motion we have initial velocity = 0.122 V, S = -1.5 meter( below ramp), acceleration = -9.8
Substituting
In case of horizontal motion
Horizontal speed of car = V cos 7 = 0.993V
So it has to travel 22 meter in t seconds
0.993Vt = 22, Vt = 22.155 m
Substituting in the equation
We will get
Speed required = 22.155/0.926 = 23.93 m/s
Minimum speed must he drive off the horizontal ramp with 7° above the horizontal = 23.93 m/s
Answer:
The horizontal component of the force,
The vertical component of the force,
Explanation:
Given;
Force on the rope, F = 35 N
angle between the rope and the horizontal = 12 °
The horizontal component of the force is given by;
The vertical component of the force is given by;