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3 years ago

If q is an odd number and the median of q consecutive integers is 120, what is the largest of these integers?

Mathematics

1 answer:

Vinil7 [7]3 years ago

6 0

We have q consecutive integers in a set and q is odd.

If 120 is the middle number, then there will be (q-1)/2 numbers

both before and after 120.

Therefore, the largest number will be (q-1)/2+120.

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How many paychecks do you get a year if you're paid semimonthly?

hjlf

Semi --> twice
semimonthly --> occuring twice a month

Thus:
You are paid twice a month

12 months in a year

12 x 2 = 24 paychecks an year

6 0

3 years ago

Scott bought a 5lb bag of cookies at the bakery. He ate 2/5 of the bag and his sister ate 2/9 of the bag. What fraction of the b

satela [25.4K]

Answer: Fraction they both eat = $\dfrac{28}{45}$ .

Fraction of bag remains = $\dfrac{17}{45}$

Step-by-step explanation:

Given: Part of cookies eaten by Scott = $\dfrac25$

Part of cookies eaten by sister = $\dfrac{2}{9}$

Fraction they both eat = $\dfrac25+\dfrac29=\dfrac{9\times2+5\times2}{5\times9}$

$=\dfrac{18+10}{45}\\\\=\dfrac{28}{45}$

Fraction of the bag remain = $1-\dfrac{28}{45}=\dfrac{45-28}{45}=\dfrac{17}{45}$

[Taking fraction of whole bag =1]

Hence, Fraction they both eat = $\dfrac{28}{45}$ .

Fraction of bag remains = $\dfrac{17}{45}$

4 0

3 years ago

What is the slope of the line in the graph?

ladessa [460]

The slope is 0 in this case because you are not moving up or down to get to the next point.
Mark me as brainliest if I helped!
Hope I did:)

8 0

3 years ago

Read 2 more answers

Urgent! Will award brainliest...<br> Factor the following polynomial:<br> <img src="https://tex.z-dn.net/?f=3a%5E%7B2%7D-21a%2B3

umka2103 [35]

Answer:

$3 (a-2) (a-5)$

Step-by-step explanation:

The first step is to find the GCF. Here, it's 3.

$3(a^2-7a+10)$

Then, you factor the polynomial in the parenthesis.

To find the factors, you will need to find 2 numbers that add to -7, and multiply to 10. -2 and -5 add to -7 and multiply to 10. Now, replace -7a with the factors.

$a^2-2a-5a+10$

This of this polynomial as 2 problems.

$a^2-2a$ $-5a+10$

Then, factor again.

$a^2-2a$ $-5a+10$

$a(a-2)$ $-5(a-5)$

Then, you keep the factors in parenthesis, and combine the numbers on the outside.

$(a-2)(a-5)(a-5)$

Since, there are 2 of the same factor, you only need one.

$(a-2)(a-5)$

BUT REMEMBER!! In the very beginning, we had a 3 that we took out, we STILL need to add that to the final answer. The <u>final answer</u> is:

$3 (a-2) (a-5)$

7 0

3 years ago

(This question is related to the picture question)

UNO [17]

Answer:

5. $f(x) = 10,000 (1.5)^x$

Step-by-step explanation:

==>>We would have to multiply the original amount by 1.50^x because the initial amount would be 1, and 50% increase would be .5 so 1.5 and you raise it to the number of years to show the total increase.

Let's test it

Initial: 10,000

After 1 year

10,000 + (.5*10000)

10,000 + 5000 = 15,000

After 2 years

15,000 + (.5*15000)

15,000 + 7500 = 22,500

Let's try our equation.

$f(x) = 10,000 (1.5)^x$

$x=2$

$10,000(1.5)^2$

$10,000(2.25) = 22,500$

*Edit: I just seen that the question is related to the picture question

6 0

3 years ago