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Dmitry [639]
3 years ago
7

Which statement describes the use of a flowchart?

Chemistry
1 answer:
Crazy boy [7]3 years ago
4 0

Answer:

idk i got 0 iQ

Explanation:

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Why is potassium nitrate classified as an electrolyte?.
ch4aika [34]

Answer: It is a molecular compound. (2) It contains a metal. (3) It can conduct electricity as a solid.

5 0
2 years ago
Why do atoms share electrons in covalent bonds??
ra1l [238]
Atoms in covalent bonds do combine so as to be stable. As covalent bond consist non metals e.g O2 in this example each atom has vacance of 2 orbitals/ electrons so shairing electrons result their stability
6 0
3 years ago
Read 2 more answers
1/ Which graph illustrates constant speed and velocity
Maksim231197 [3]
Velocity is said to be constant if its magnitude as well direction at any instant is remains the same. In D, if you draw a line parallel to y-axis at any time t, you can see that velocity is same. Hence, D is the correct graph.

The kinetic energy of gaseous molecules is greater than that of liquid molecules. Therefore, in gas, kinetic energy overcomes the force of attraction between molecules. In short, in gas phase, particles move at high speed and hence they have less force of attraction. In case of liquid phase, particles are close enough as a result there is much more force of attraction compared to gaseous molecules. In liquid state, kinetic energy cannot overcome force of attraction therefore, liquid molecules slow down.

Therefore, B is the correct answer.
4 0
3 years ago
A patient arrives in the emergency with a burn caused by steam. Calculate the heat that released when 17.7 g of steam
MaRussiya [10]

The steam releases 39.9 kJ when it condenses..

The steam condenses and transfers its energy to the skin.

<em>q = m</em>Δ<em>H</em>_cond = 17.7 g × (-2257 J/1 g) = -39 900 kJ = -39.9 kJ

The negative sign shows that the steam is releasing energy

3 0
3 years ago
Gaseous methane (CH4) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO) and gaseous water (H2O) . Suppo
Leto [7]

Answer:

0 g.

Explanation:

Hello,

In this case, since the reaction between methane and oxygen is:

CH_4+2O_2\rightarrow CO_2+2H_2O

If 0.963 g of methane react with 7.5 g of oxygen the first step is to identify the limiting reactant for which we compute the available moles of methane and the moles of methane consumed by the 7.5 g of oxygen:

n_{CH_4}=0.963gCH_4*\frac{1molCH_4}{16gCH_4}=0.0602molCH_4\\ \\n_{CH_4}^{consumed}=7.5gO_2*\frac{1molO_2}{32gO_2}*\frac{1molCH_4}{2molO_2} =0.117molCH_4

Thus, since oxygen theoretically consumes more methane than the available, we conclude the methane is the limiting reactant, for which it will be completely consumed, therefore, no remaining methane will be left over.

left\ over=0g

Regards.

7 0
2 years ago
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