Basically
just put the coeficinets of each variable in the apropriate row
example
ax+by=c and
dx+ey=f
would go in like this
![\left[\begin{array}{ccc}a&b&|c\\d&e&|f\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%26%7Cc%5C%5Cd%26e%26%7Cf%5Cend%7Barray%7D%5Cright%5D%20)
so
3x+1=1 and
0x-1y=5
![\left[\begin{array}{ccc}3&1&|1\\0&-1&|5\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%26%7C1%5C%5C0%26-1%26%7C5%5Cend%7Barray%7D%5Cright%5D%20)
D is answer
Answer:
a. h = 60t − 4.9t²
b. 12.2 seconds
c. 183.7 meters
Step-by-step explanation:
a. Given:
y₀ = 0 m
v₀ = 60 m/s
a = -9.8 m/s²
y = y₀ + v₀ t + ½ at²
h = 0 m + (60 m/s) t + ½ (-9.8 m/s²) t²
h = 60t − 4.9t²
b. When the ball lands, h = 0.
0 = 60t − 4.9t²
0 = t (60 − 4.9t)
t = 0 or 12.2
The ball lands after 12.2 seconds.
c. The maximum height is at the vertex of the parabola.
t = -b / (2a)
t = -60 / (2 × -4.9)
t = 6.1 seconds
Alternatively, the maximum height is reached at half the time it takes to land.
t = 12.2 / 2
t = 6.1 seconds
After 6.1 seconds, the height reached is:
h = 60 (6.1) − 4.9 (6.1)²
h = 183.7 meters
In this you have to do 6(total) /(Divided) 2/3. And when you do 6/(2/3) you also have to do KCF(keep, change, flip) and that brings you to 18/2 after multiplying across. So the answer would be 9 people.
<span>a.) Let x be the number of tickets sold before the event and y the number of tickets sold on the day of the event. Then x + y =< 800 and 6x + 9y >= 5000. (b.) Suppose the club sold 440 tickets before the event, i.e. x = 440, maximum number of tickets remaining to be sold = 800 - 440 = 360. Maximum amount realized from the sales supposing all tickets were sold = 6(440) + 9(360) = 2640 + 3240 = $5880 which is greater than $5000. Therefore, it is possible for the club to sell enough additional tickets on the day of the show to meet the expenses of the show.</span>
Answer:
It could be a rectangle with a length of 25 and a width of 15.
Step-by-step explanation:
Just basically multiply the ratio by common factor to create the rectangle dimensions.
