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3 years ago

Which expression is equivalent to 12/15? A. 25÷12 B. 12÷25 C. 12÷1/25 D. 25÷1/12

Mathematics

1 answer:

Rudiy273 years ago

7 0

Answer:

None of the answers are correct, because 12/15=4/5, it's equivalent to 12 divided by 15.

Step-by-step explanation:

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Hi!pls can u help me factorise this

soldier1979 [14.2K]

Answer:

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Step-by-step explanation:

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3 years ago

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Which monomials are divisible by 6y^2?

kifflom [539]

Answer:

A) $12y^{3}$

Step-by-step explanation:

A) $\frac{12y^{3} }{6y^{2} }$

$=\frac{2y(6y^{2} )}{6y^{2}}$

= 2y

B) $\frac{24y}{6y^{2} }$

$=\frac{4}{y}$

Hence, $12y^{3}$ is divisible by $6y^{2}$ and the correct option is (A).

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3 years ago

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6x-2y=48 <br> Find the y and x intercept <br> Write in ordered Pairs

Andrej [43]

Answer:

Correct you are correct

Step-by-step explanation:

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3 years ago

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Consider the implicit differential equation <img src="https://tex.z-dn.net/?f=%2849%20y%5E%7B3%7D%20%2B%2045%20xy%29%20dx%20%2B%

BaLLatris [955]

We're looking for an integrating factor $\mu(x,y)=x^py^q$ such that

$\mu\underbrace{(49y^3+45xy)}_M\,\mathrm dx+\mu\underbrace{(98xy^2+50x^2)}_N\,\mathrm dy=0$

is exact, which would require that

$(\mu M)_y=(\mu N)_x$
$(49x^py^{q+3}+45x^{p+1}y^{q+1})_y=(98x^{p+1}y^{q+2}+50x^{p+2}y^q)_x$
$49(q+3)x^py^{q+2}+45(q+1)x^{p+1}y^q=98(p+1)x^py^{q+2}+50(p+2)x^{p+1}y^q$
$\implies\begin{cases}49(q+3)=98(p+1)\\45(q+1)=50(p+2)\end{cases}\implies p=\dfrac52,q=4$

You can verify that $(\mu M)_y=(\mu N)_x$ if you'd like. With the ODE now exact, we have a solution $F(x,y)=C$ such that

$F_x=\mu M$
$F=\displaystyle\int(49y^3+45xy)x^{5/2}y^4\,\mathrm dx$
$F=10x^{9/2}y^5+14x^{7/2}y^7+f(y)$

$F_y=\mu N$
$50x^{9/2}y^4+98x^{7/2}y^6+f'(y)=98x^{7/2}y^2+50x^{9/2}y^4$
$f'(y)=0$
$\implies f(y)=C$

and so the general solution is

$F(x,y)=10x^{9/2}y^5+14x^{7/2}y^7=C$

8 0

3 years ago

Callies family spends an average of $70 per month electric at that rate what can that family expect to pay electric for 1 year

ivanzaharov [21]

Answer:

$840

Step-by-step explanation:

Callies family spends an average of $70 per month electric. At that rate what can that family expect to pay electric for 1 year

Note that:

1 year = 12 months.

Hence, if:

1 month = $70

12 months = $x

Cross Multiply

$x = 12 × $70

$x = $840

Therefore, the amount that family can expect to pay in 1 year(12 month) for electric = $840

4 0

3 years ago