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docker41 [41]
3 years ago
10

Monica deposits $100 into a savings account that pays a simple intrest rate of 3.4%. Paul deposits $200 into a savings account t

hat pays a simple intrest rate of 2.2%.
Mathematics
1 answer:
Goshia [24]3 years ago
6 0

Answer:

Paul

Step-by-step explanation:

Paul earn more than monica. Though he is getting less interest but because of his higher initial amount he is getting more return.

Computing the return of both

Monica return is  100*3.4%= $3.4 in a year

Paul return is 200*%2.2=  $4.4 in a year.

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The first part of the second line, she left the -5 there. The correct work and solution should be this:
5(2x-1)-3x=5x+9
<span><span>7x</span>−5</span>=<span><span>5x</span>+<span>9
</span></span>2x-5=9
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3 years ago
Help!!! Whats The answer, Please explain your answer Marking brainlliest:D......
Elina [12.6K]
The answer would be 96 square feet length

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4 0
2 years ago
HELPPP ASAP PLEASEEE THANK YOU
ahrayia [7]

Step 1: Find the slope

Slope formula = (y2 - y1) / (x2 - x1)

---You can choose any two points when finding the slope!

Point 1 = (-2,-10)

Point 2 = (-1,-3)

Slope = (-3 - - 10) / (-1 - - 2)

Slope = 7 / 1

Slope = 7

Step 2: Find the y-intercept

Now that we have the slope, we'll plug that and one point into slope-intercept form. Then, we'll solve for b.

Slope-Intercept Form: y = mx + b

---m is the slope, b is the y-intercept

Point = (-1, -3)

Slope = 7

-3 = 7(-1) + b

-3 = -7 + b

b = 4

Step 3: Put it all together

Now that we know the slope and y-intercept, all that's left to do is plug them into slope-intercept form.

Slope-Intercept Form: y = mx + b

Slope = 7

Y-Intercept = 4

Line: y = 7x + 4

Correct Answer: A

Hope this helps!

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2 years ago
A rectangular prism must have a base with an area of no more than 27 square meters. The width of the base must be 9 meters less
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Answer:

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2 years ago
A scientist is studying the population growth rates of two different species of rats in the same laboratory conditions. The popu
Korolek [52]

Since, population of species A is represented by : P=2^{x} +19

Let us find the population of species A, at the end of week 1:

i.e., x = 1

i.e., P(1)=2^{1} +19

i.e., P(1)=2 +19

i.e., P(1)=21


Also, since population of species B is represented by : P=3^{x} +18

Let us find the population of species B, at the end of week 1:

i.e., x = 1

i.e., P(1)=3^{1} +18

i.e., P(1)=3 +18

i.e., P(1)=21


Thus, at the end of 1 week, species A and species B will have the same population.

Hence, option D is correct.

4 0
3 years ago
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