Answer:
sad:times
Step-by-step explanation:
where is the s in here though
Answer:
Yes, "y" varies directly with "x".
The equation is: 
Step-by-step explanation:
By definition, Direct variation equations have the following form:

Where "k" is the Constant of variation.
If you solve for "k", the equation is:

Then, given the table provided in the exercise, you can know if "y" varies directly with "x" by finding the quotient of the correspoding values of "x" and "y":
- Dividing
by
you get:

- Divide
by
:

- Dividing
by
:

Since the quotient is constant, then "y" varies directly with "x" and the the Constant of variation is:

Therefore, the equation for the Direct variation is:

Answer:
Im not sure what type of solution you are looking for. You should be more specific. Though I will still give you some helpful solutions and you use the one you need.
Step-by-step explanation:
Factored: y=168x+67y-49
Solved for Y; -28x/11 + 49/66
Solved for X: -11y/28 + 7/24
X and Y intercepts:
X=( 7/24, 0 )
Y= ( 0, 49/66 )
I hope these answers help. Next time be more specific to what your looking for and make sure your equation is written correctly.