An equation of line with a slope of 1/3 and containing the point (-4,7) is
y = 1/3 x + 25/7
In this question, we have been given
slope (m) = 1/3
and a point (-4, 7)
We need to find an equation of a line with a slope of 1/3 and containing the point (-4,7)
Using the formula for the slope-point form of equation of line,
y - y1 = m(x - x1)
y - 7 = 1/3(x + 4)
y - 7 = (1/3)x + 4/3
y = (1/3)x + 4/3 + 7
y = 1/3 x + 25/7
Therefore, an equation of line with a slope of 1/3 and containing the point (-4,7) is y = 1/3 x + 25/7
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Answer:
y = -4x+1
Step-by-step explanation:
slope = (y2-y1)/ (x2-x1)
m= (-3-5)/(1--1)
= (-3-5)/(1+1)
= -8/2
= -4
point slope form of a line is
y-y1 = m(x-x1)
y-5 =-4(x--1)
y-5 = -4 (x+1)
distribute
y-5 = -4x -4
add 5 to each side
y-5+5 = -4x-4+5
y = -4x+1
Basically use the formula y1-y2 over x1-x2 and just plug in the number
I hope this helps you
x=-5 f (-5)=4. (-5)^2 =4.25=100
x=0 f(0)=4.0^2=4.0=0
x=5 f (5)=4.5^2=4.25=100
The expected value of the number of points for each turn is 0.25
<h3>What is expected value?</h3>
Expected value describes the long term average level of a random variable based on its probabilty distribution.
Now, Probability that 2 heads come up is
P(2 is H) = 1/4
Probability that 1 heads come up is
P(1 is H) = 2/4
⇒P(1 is H) = 1/2
Probability that no head will come up
P(no H's) = 1/4
Hence, the expected value for winning of 2points, 1point and lose of3 points is given as-
Expected value = 2 * P(2 is H) + 1 * P(1 is H) - 3 * P(no H's)
⇒Expected value = 2 * 1/4 + 1 * 1/2 - 3 * 1/4
= 0.5 + 0.5 - 0.75
⇒Expected value = 0.25
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