Sin2x = 2 sinx cosx
so 12 sinx cosx = 6 sin2x Answer
Answer:
If we arrange the talks from the lowest starting time to the highest ending time we get total of 11 talks.
using algorithm 7 we get answer (1) - (3) - (6) - (9) the largest number of talks scheduled.
Step-by-step explanation:
arranging the talks from lowest starting time to the highest ending time.
thus,
- 9:00 a.m. and 9:45 a.m.
- 9:30 a.m. and 10:00 a.m.
- 9:50 a.m. and 10:15 a.m.
- 10:00 a.m. and 10:30 a.m.
- 10:10 a.m. and 10:25 a.m.
- 10:30 a.m. and 10:55 a.m.
- 10:15 a.m. and 10:45 a.m.
- 10:30 a.m. and 11:00 a.m.
- 10:45 a.m. and 11:30 a.m.
- 10:55 a.m. and 11:25 a.m.
- 11:00 a.m. and 11:15 a.m.
we start from the earliest time as
9:00 a.m. and 9:45 a.m which is (1).
After the talk is finished we pick the nearest time for another talk which starts at
9:50 a.m. and 10:15 a.m which is (3).
After this talk we again pick the nearest time for another talk which becomes
10:30 a.m. and 10:55 a.m which is (6).
and lastly
10:45 a.m. and 11:30 a.m which is (9).
Note: we didn't choose other times because we cannot talk at 2 or 3 places at the same time. so we pick another when one talk is finished.
thus the answer is (1) - (3) - (6) - (9) as the largest number of talks scheduled.
5
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Answer:
Step-by-step explanation:
- The concept of demand is applied, demand may be elastic, inelastic and unitary as the detailed steps and calculations is as shown in the attached file.
- For elastic demand, P > 1
- For inelastic demand, P < 1
- For unitary, P = 1
