Question

What is the missing value of (x,2) and (6,3); m=1/2 using the slope?

Answer 1

$\bf (\stackrel{x_1}{x}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{x}}}~~ = ~~\stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{2}}\implies \cfrac{1}{6-x}=\cfrac{1}{2}\implies 2=6-x \\\\\\ x+2=6\implies x = 4$