Answer:
Step-by-step explanation:
For complete solution kindly refer to the attachment .
Step-by-step explanation:
y-4 = 5x -40
-5x + y = -36
y = -3/5x + 2
y-2 = -3/5x
5y - 10 = -3x
3x + 5y = 10
<h3>Given</h3>
- length, width, and height of a cuboid are x, x, and 2x, respectively
- the cuboid's surface area is 129.6 cm²
- dx/dt = 0.01 cm/s
<h3>Find</h3>
- dV/dt for the given conditions
<h3>Solution</h3>
The equation for surface area can be written
... A = 2(LW +H(L +W))
Substituting the given values gives an equation that we can solve for x
... 129.6 = 2(x·x +2x(x +x)) = 10x²
... x = √(129.6/10) = 3.6 . . . . . . . cm
The equation for volume can be written
... V = LWH
Substituting the given values gives an expression for volume in terms of x.
... V = x·x·2x = 2x³
Then the rate of change of volume is
... dV/dt = 6x²·dx/dt
... dV/dt = 6·(3.6 cm)²·(0.01 cm/s)
... dV/dt = 0.7776 cm³/s
Answer:
Which statement is true about the angles? Answer is measure B is = 60 which is B
Step-by-step explanation:
took the test
<span>The formula to find the period of orbit of a satellite around a planet is T^2=(4π^2/GM)r^3 where r is the orbit’s mean radius, M is the mass of the planet, and G is the universal gravitational constant. To find the value of r, we rewrite r^3 = (T^2GM/4π^2) or r = (T^2GM/4π^2)^(1/3)</span>
