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Ghella [55]
4 years ago
5

Describe how to graph point K at (5,4)

Mathematics
2 answers:
Slav-nsk [51]4 years ago
8 0

Answer & Step-by-step explanation:

K(5,4)

Remember this:

(x,y)

(5_{x},4_{y})

When you are going to graph a point, you always start along the x-axis (the horizontal), then you move on to the y-axis (vertical). Both of the numbers in K are positive, so we will stay in Quadrant I.

For x, starting at (0,0) move to the right to point 5. From here, move up to the line that has value 4. Mark this spot with a dot and label if needed.

*If the x value is positive, you move to the right. If it is negative, you move to the left.

If the y value is positive, you move up. If it is negative, you move down.

LiRa [457]4 years ago
6 0
Start at (0,0) go to the right 5 spaces then go up 4 spaces. put a point where you end up
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A blue whale traveled 31 1/2 miles in 2 1/4 hours. What was the whales rate in yards per hour ( 1 mile = 1,760 yards
tekilochka [14]

Answer: 25594.018691648 yards per hour

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14.5420560748×1760=25594.018691648

Step-by-step explanation:

6 0
3 years ago
To make a monster appear large in a movie, a human actor wore a costume and walked through a scale model of a city. The scale us
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The answer is 60*15, or 900 feet.
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5 Solve for x. 8 = 2x + 4​
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Answer:

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A running circuit is in the shape of a triangle with lengths of 6km, 6.5km and 7km. What are the sizes of the angles (in minutes
Rudik [331]

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}. The <em>measures</em> of the internal <u>angles</u> of the <u>triangle</u> given in the question are A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}.

Considering the given question, let the <u>sides</u> of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.

Apply the <em>Cosine rule</em> to have:

c^{2} = a^{2} + b^{2} - 2ab Cos C

So that;

7^{2} = 6^{2} + (6.5)^{2} - 2(6 * 6.5) Cos C

49 = 36 + 42.25 - 78Cos C

78 Cos C = 78.25 - 49

               = 29.25

Cos C = \frac{29.25}{78}

         = 0.375

C = Cos^{-1} 0.375

   = 67.9757

C = 68^{o}

Apply the <em>Sine rule</em> to determine the <u>value</u> of B,

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{6.5}{Sin B} = \frac{7}{Sin 68}

SIn B = \frac{6.5 *Sin 68}{7}

         = 0.861

B = Sin^{-1} 0.861

   = 59.43

B = 59.4^{o}

Thus to determine the value of A, we have;

A + B + C = 180^{o}

A + 59.4^{o} + 68^{o} = 180^{o}

A = 180^{o} - 127.4

  = 52.6

A = 52.6^{o}

Therefore the <u>sizes</u> of the <em>internal angles</em> of the triangle are: A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814

#SPJ1

8 0
2 years ago
Find the equation of a line passing through a point (3,5) and perpendicular to the line joining the points (3, 7) and (7, -1)
eduard

Step-by-step explanation:

we start first by finding the gradient of the line

change in y/change in x

7-(-1)/3-7=8/-4

=-2

then for perpendicular lines m1m2=-1

therefore to find the gradient of that line

-2m2=-1

therefore m2=2

so therefore

y-5/x-3=2

so y-5=2x-6

y-2x=-1

in the form y= mx +c

then y=2x-1

7 0
2 years ago
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