4 because if you round to 2 and .5, then it would be easier to tell
236.5% is the correct answer
Answer:
the first one because it has more flowers
Step-by-step explanation:
For this case what you should know is that both functions are of the potential type.
We have then that
y = 2 * 2 ^ x This function grows exponentially upwards.
y = -2 * 5 ^ x This function grows exponentially downwards.
Answer See attached graphics.
Answer:
The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for the difference between population means is:
![CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}](https://tex.z-dn.net/?f=CI%3D%28%5Cbar%20x_%7B1%7D-%5Cbar%20x_%7B2%7D%29%5Cpm%20z_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csqrt%7B%5Cfrac%7B%5Csigma%5E%7B2%7D_%7B1%7D%7D%7Bn_%7B1%7D%7D%2B%5Cfrac%7B%5Csigma%5E%7B2%7D_%7B2%7D%7D%7Bn_%7B2%7D%7D%7D)
The information provided is as follows:
![n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43](https://tex.z-dn.net/?f=n_%7B1%7D%3D%20138%5C%5Cn_%7B2%7D%3D156%5C%5C%5Cbar%20x_%7B1%7D%3D61%5C%5C%5Cbar%20x_%7B2%7D%3D64.6%5C%5C%5Csigma_%7B1%7D%3D18.53%5C%5C%5Csigma_%7B2%7D%3D13.43)
The critical value of <em>z</em> for 98% confidence level is,
![z_{\alpha/2}=z_{0.02/2}=2.326](https://tex.z-dn.net/?f=z_%7B%5Calpha%2F2%7D%3Dz_%7B0.02%2F2%7D%3D2.326)
Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:
![CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}](https://tex.z-dn.net/?f=CI%3D%28%5Cbar%20x_%7B1%7D-%5Cbar%20x_%7B2%7D%29%5Cpm%20z_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csqrt%7B%5Cfrac%7B%5Csigma%5E%7B2%7D_%7B1%7D%7D%7Bn_%7B1%7D%7D%2B%5Cfrac%7B%5Csigma%5E%7B2%7D_%7B2%7D%7D%7Bn_%7B2%7D%7D%7D)
![=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)](https://tex.z-dn.net/?f=%3D%2861-64.6%29%5Cpm%202.326%5Ctimes%5Csqrt%7B%5Cfrac%7B%2818.53%29%5E%7B2%7D%7D%7B138%7D%2B%5Cfrac%7B%2813.43%29%5E%7B2%7D%7D%7B156%7D%7D%5C%5C%5C%5C%3D-3.6%5Cpm%204.4404%5C%5C%5C%5C%3D%28-8.0404%2C%200.8404%29%5C%5C%5C%5C%5Capprox%20%28-8.04%2C%200.84%29)
Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).