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1 year ago

Solve: 5.6 = 3.1 – 12.5|1 – 0.8x|

Mathematics

1 answer:

galben [10]1 year ago

5 0

Answer:

<h3>There are no solutions.</h3>

Step-by-step explanation:

Questions:

Solve: 5.6= 3.1 – 12.5|1 – 0.8x|

To find:

The value of x.

Solutions:

5.6= 3.1 – 12.5|1 – 0.8x|

First, do switch sides.

$\Longrightarrow:\sf{3.1-12.5\left|1-0.8x\right|=5.6}$

Multiply by 10 from both sides.

$\Longrightarrow: \sf{3.1*10-12.5|1-0.8x|*10=5.6*10}$

Solve.

31-125|1-0.8x|=56

Subtract by 31 from both sides.

$\Longrightarrow: \sf{31-125\left|1-0.8x\right|-31=56-31}$

Solve.

$\Longrightarrow: \sf{-125\left|1-0.8x\right|=25}$

Divide by -125 from both sides.

Solve.

$\Longrightarrow: \sf{\dfrac{-125\left|1-0.8x\right|}{-125}=\dfrac{25}{-125}=\boxed{\sf{No\ solutions.}}}$

Therefore, the correct answer is "D. There are no solutions."

I hope this helps, let me know if you have any questions.

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Do you need to ask a question, but don't have points.....

horsena [70]

Yes, felt that. thanks and have a lovely day!:D

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2 years ago

Read 2 more answers

A college conducts a common test for all the students. For the Mathematics portion of this test, the scores are normally distrib

Jet001 [13]

Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 502, \sigma = 115$

The proportion of students between 400 and 590 is the p-value of Z when X = 590 subtracted by the p-value of Z when X = 400, hence:

X = 590:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{590 - 502}{115}$

Z = 0.76

Z = 0.76 has a p-value of 0.7764.

X = 400:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{400 - 502}{115}$

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

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6 0

1 year ago

HELP FAST I'LL MARK YOU BRAINLIEST

Elden [556K]

Answer:

y = -2x + 12

Step-by-step explanation:

Step 1: find the slope

y = 1/2x + 5

The equation of the line is

y = mx + c

m - slope

m = 1/2

Note : if two lines are perpendicular to the other, both lines are negative reciprocal of each other

m = -2

Step 2 : using a point slope form

y - y1 = m( x - x1)

( 2 , 5)

x1 = 2

y1 = 5

y - 2 = -2( x - 5)

y - 2 = -2x + 10

y = -2x + 10 + 2

y = -2x + 12

The equation of the line is

y = -2x + 12

I dunno the answer so I just found another answer I found in here for this question:P

Sorry- it’s useless

5 0

2 years ago

NEED HELP ASAP PLEASE!!

qwelly [4]

Option D:

$$y=\frac{5x-2}{x}$

Solution:

Given function:

$$y=\frac{-2}{x-5}$

To find the inverse of the function.

Inverse of a function:

If a function f(x) is mapping x to y, then the inverse function of f(x) maps y back to x.

$$y=\frac{-2}{x-5}$

Interchange the variables x and y.

$$x=\frac{-2}{y-5}$

Now, solve for y.

Multiply both sides by (y - 5).

$$x(y-5)=-\frac{2}{y-5}(y-5)$

Cancel the common factors, we get

$x(y-5)=-2$

Divide by x on both sides.

$$y-5=-\frac{2}{x}$

Add 5 on both sides.

$$y=-\frac{2}{x}+5$

$$y=-\frac{2}{x}+\frac{5}{1}$

To make the denominator same, multiply the 2nd term by $\frac{x}{x}$ .

$$y=-\frac{2}{x}+\frac{5x}{x}$

$$y=\frac{-2+5x}{x}$

$$y=\frac{5x-2}{x}$

Option D is the correct answer.

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2 years ago

Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2

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$\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------$

$\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o$

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2 years ago