Answer: The correct option is fourth, i.e., SSS.
Explanation:
First write the name of vertices as shown below,
From the figure we can say that in triangle DAB and triangle BCD,
In both triangle the sides BD is common, so,
Since three sides of triangles DAB and triangle BCD are same so by the SSS property of congruent triangle we can conclude that the triangle DAB and triangle BCD are congruent.
Therefore the fourth option is correct.
g(1)=-1 : We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.
So, g(1)=-1 is false.
g(0)=0 : We need to check values of function for x=0. From the graph, we can see, for x=0 the value of y is 0.
So, g(0) =0 is true.
g(4)=-2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to -2.
So, g(4)=-2 is false.
g(1)=1 :We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.
So, g(1) =1 is true.
g(-1)=1 :We need to check values of function for x=-1. From the graph, we can see, for x=-1 the value of y is 1.
So, g(-1)=1 is true.
g(4)=2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to 2.
So, g(4)=2 is false.
