All categories

3 years ago

Find an ordered pair (x,y) that is a solution to the equation. 3x-y=8

Mathematics

1 answer:

allochka39001 [22]3 years ago

7 0

Answer:

(2,-2)

Step-by-step explanation:

$3x-y =3(2) -(-2)= 6 +2 = 8$

You might be interested in

Hahaha help:)))))))))

Viefleur [7K]

Answer:

1332 i think is how it will be writen

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have

boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.

We will use half life formula.

$A=a\cdot(\frac{1}{2})^{\frac{t}{h}}$ , where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{1}$

$A=1\text{ kg}\cdot\frac{1}{2}$

$A=0.5\text{ kg}$

Therefore, amount of the material left after 10 days would be 0.5 kg.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{2}$

$A=1\text{ kg}\cdot\frac{1^2}{2^2}$

$A=1\text{ kg}\cdot\frac{1}{4}$

$A=0.25\text{ kg}$

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0

3 years ago

Are the following figures similar?

Tcecarenko [31]

No the corresponding angles are not congruent, because the angle measures on the smaller figure are 90, 90, 137, and 43, while the larger figure has angle measures of 90, 90, 136, 44. that is why the following figures are not congruent.

3 0

3 years ago

If the following fractions were converted to decimals, which one would result in a repeating decimal?

Sveta_85 [38]

B. 3/7
...................

4 0

3 years ago

Read 2 more answers

Moonshine Problem: How many gallons of 20% moonshine and how many gallons of 30% moonshine have to be mixed together to make 100

Sindrei [870]

Answer:

50 gallons 20%

50 gallons 30%

Step-by-step explanation:

If x is gallons of 20% moonshine, and y is gallons of 30% moonshine, then:

x + y = 100

0.20x + 0.30y = 0.25(100)

Solve the system of equations using substitution or elimination. Using substitution:

0.20x + 0.30(100 − x) = 0.25(100)

0.20x + 30 − 0.30x = 25

5 = 0.10x

x = 50

y = 50

3 0

3 years ago