Mode is the answers that occurs the most frequently in a data set. So it’s 3-4 inches.
Answer:
A
Step-by-step explanation:
3x × 4 =12x
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A kickball is a sphere, so to solve this, we are going to use the formula for the volume of a sphere:
![V= \frac{1}{6} \pi d^3](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B1%7D%7B6%7D%20%20%5Cpi%20d%5E3)
where
![V](https://tex.z-dn.net/?f=V)
is the volume of the sphere.
![d](https://tex.z-dn.net/?f=d)
is the diameter of the sphere.
We know form our problem that the diameter of the kickball is 10 inches; since the kickball is a sphere,
![d=10in](https://tex.z-dn.net/?f=d%3D10in)
. Lets replace that value in our formula to find
![V](https://tex.z-dn.net/?f=V)
:
![V= \frac{1}{6} \pi d^3](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B1%7D%7B6%7D%20%5Cpi%20d%5E3)
![V= \frac{1}{6} \pi (10in)^3](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B1%7D%7B6%7D%20%5Cpi%20%2810in%29%5E3)
![V=523.6in^3](https://tex.z-dn.net/?f=V%3D523.6in%5E3)
We can conclude that the volume of the kickball is
523.6 cubic inches.
By Green's theorem,
![\displaystyle\int_C(9y+x)\,\mathrm dx+(y+3x)\,\mathrm dy=\iint_D\frac{\partial(y+3x)}{\partial x}-\frac{\partial(9y+x)}{\partial y}\,\mathrm dy\,\mathrm dx=-6\iint_D\mathrm dy\,\mathrm dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint_C%289y%2Bx%29%5C%2C%5Cmathrm%20dx%2B%28y%2B3x%29%5C%2C%5Cmathrm%20dy%3D%5Ciint_D%5Cfrac%7B%5Cpartial%28y%2B3x%29%7D%7B%5Cpartial%20x%7D-%5Cfrac%7B%5Cpartial%289y%2Bx%29%7D%7B%5Cpartial%20y%7D%5C%2C%5Cmathrm%20dy%5C%2C%5Cmathrm%20dx%3D-6%5Ciint_D%5Cmathrm%20dy%5C%2C%5Cmathrm%20dx)
where
is the disk with
as its boundary. The integral is simply -6 times the area of the disk
, which has radius √6, and hence area 6π, so the value of the integral is -36π.
Answer:
20 hours
Step-by-step explanation:
20x20