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bezimeni [28]
3 years ago
8

10. A cliff on the seashore is eroding at the rate of 17 centimeters per year. Write and solve an equation to find the number of

Mathematics
1 answer:
katovenus [111]3 years ago
7 0

Answer:

The answer is 5 years

Step-by-step explanation:

You must do 85 cm ÷ 17 cm to find how many years in which the cliff will erode 85 centimeters and the answer is 5.

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15 pounds of beans are distributed equally into 10 bags to give out at the food bank. How many pounds of beans are in each bag?
Tems11 [23]

Answer:

1.5, or 1 1/2

Step-by-step explanation:

8 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
What is the answer to this?
tensa zangetsu [6.8K]
The answer is b!!!!!
6 0
3 years ago
Help pls 6th grade math i will give brainliest
SCORPION-xisa [38]

Answer:

G because y+y+y is the exact same as 3 y

5 0
3 years ago
Read 2 more answers
Write the ratio as a ratio of whole numbers in lowest terms<br><br> $1.00 to $0.80
diamong [38]
5/4
as 1.00/0.80 = 100/80
and then when you simplify it the answer would be 4/5.
6 0
3 years ago
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