Show that the equation x^3+7x-4=0 has a solution between x=0 and x=1
1 answer:
Step-by-step explanation:
Using the Intermediate Value Theorem, the following is applied:
"If f(x) is a continuous on interval [a,b] and we have two points f(a) and f(b) then there must be some value c such that f(a)<f(c)<f(b).
So here there must be a c such that
Note: F(c)=0, the questions that the function have a solution between 0 and 1, so that means we must have some value, c such that f(c)=0 that exists
Next, plug in the x values into the function
Since cubic functions are continuous and -4<0<4, then there is a solution c that lies between f(0) and f(1)
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