V = (pi) * r^2 * h
h = 7
V = 252(pi)
252(pi) = r^2 * 7
252(pi) / 7 = r^2
36(pi) = r^2
sqrt 36(pi) = r
6 = r <==== radius is 6 cm
3) Vertex: (-7, 0) Axis of Symmetry: x=-7
6) Vertex: (-2, -1) Axis of Symmetry: x=-2
Answer:
The discriminant of f is 92, and it has no real zeros
Step-by-step explanation:
The discriminant of a quadratic is
, where the quadratic is in the form
. The discriminant of this one is therefore:

Since the square root of a negative number is imaginary, this quadratic has no real number zeros. Hope this helps!
Answer: 
<u>Step-by-step explanation:</u>
The explicit rule for a geometric sequence is: 
The information provided is: a₁ =
and r = 5

-30-27= -57
When both numbers are negative, they are “added” in a sense, but remain negative.
-5-(-4)= -1
You have to multiply the (-4) by the “invisible” -1 on the outside before you add/subtract.