All categories

3 years ago

Explain how 3/4 and 6/8 are the same

2 answers:

5 0

Fundamentally, if you simplify 6/8, you would get 3/4. But here is a better-explained reasoning:

$\frac{6}{8}$ ÷ $\frac{2}{2}$ = $\frac{3}{4}$

Vlada [557]3 years ago

5 0

One way you can tell they are the same is if you simply 6/8, you divide both numbers by two and you get 3/4. Another way you can tell is see how many time four goes into eight. It goes in twice, so you multiply your denominator by two. My teacher taught me whatever you do to the bottom, you do to the top. So you do three times two and you get six. That's how 3/4 and 6/8 are the same.

You might be interested in

Erik needs a plumber and must decide between two companies. For a service visit, Plumber A charges $85 to send a plumber, plus $

djverab [1.8K]

C. Plumber A and Plumber B will both charge $135 if they each work 2.5 h.

6 0

4 years ago

Y greater than or equal to x + 4

tatiyna

See the attached files

<h2>Explanation:</h2>

Here we have the following inequality:

$y>x+4$

In order to graph the shaded region, we have to graph the equation of the line $y=x+4$ whose slope is $m=1$ and y-intercept $b=4$ . So the graph of the line is shown in the First Figure below.

To find the shaded region we need to have a look at the symbol > that indicates that the shaded region is above the graph of the line and. Since this doesn't include the symbol =, then the line is dotted. Therefore, the resulting region is shown in the second Figure.

<h2>Learn more:</h2>

Shaded regions: brainly.com/question/9611462

#LearnWithBrainly

5 0

3 years ago

Find the reciprocal of 1/5

ivanzaharov [21]

Answer:

Hey! The reciprocal of 1/5 is 5!

Hope this helps :)

~sofia

6 0

4 years ago

For which values of k does the system of linear equations have zero, one, or an infinite number of solutions? [Note: not all thr

viktelen [127]

Answer:

The system has an infinite solution at k = 6, otherwise for any value of k, it has zero solution.

Step-by-step explanation:

Consider the system of linear equations:

$3x_{1} -x_{2}=2\;\;\;\;\;\;(1)\\ 9x_{1} -3x_{2}=k\;\;\;\;\;(2)$

The system of linear equations can have zero, one, or an infinite number of solutions:

simplify equation (1):

$x_{2}=3x_{1} -2$

substitute in equation (2), we get

$9x_{1} -3(3x_{1}-2)=k\\9x_{1} -9x_{1}+6=k\\0+6=k$

we cannot find the value of $x_{1}$ and $x_{2}$ .

so, there is no solution.

Multiply the equation (1) with 3 and put k is 6,

$3(3x_{1} -x_{2})=3\times2\\9x_{1} -3x_{2})=6$

it means both equations are overlapped. Then, the solution has infinite solutions.

Hence, the system has an infinite solutions at k is 6 otherwise for any value of k it has no solution.

4 0

3 years ago

show that the sum of the x- and y- intercepts of any tangent line to the curve sqrt(x) sqrt(y) = sqrt(c) is equal to c.

expeople1 [14]

The answer is √x + √y = √c 
=> 1/(2√x) + 1/(2√y) dy/dx = 0 
=> dy/dx = - √y/√x 

Let (x', y') be any point on the curve 
=> equation of the tangent at that point is 
y - y' = - (√y'/√x') (x - x') 

x-intercept of this tangent is obtained by plugging y = 0 
=> 0 - y' = - (√y'/√x') (x - x') 
=> x = √(x'y') + x' 

y-intercept of the tangent is obtained by plugging x = 0 
=> y - y' = - (√y'/√x') (0 - x') 
=> y = y' + √(x'y') 

Sum of the x and y intercepts 
= √(x'y') + x' + y' + √(x'y') 
= (√x' + √y')^2 
= (√c)^2 (because (x', y') is on the curve => √x' + √y' = √c) 
= c. hope this helps :D

5 0

3 years ago