Answer:
Kindly check explanation
Step-by-step explanation:
Given that:
Cost per bracelet = 1.50
Cost per necklace = 2.25
Let :
number of necklace = n
Number of bracelet = b
Cost equation C ;
C = 1.5b + 2.25n
Number of necklace that could be sold for exactly $12
5 necklaces and 1 bracelet :
1.5 + 2.25(5) = 12.75
•2 necklaces and 5 bracelets:
1.5(5) + 2.25(2) = 12
• 3 necklaces and 3 bracelets
1.5(3) + 2.25(3) = 11.25
• 4 necklaces and 2 bracelets
1.5(2) + 2.25(4) = 12
• 3 necklaces and 5 bracelets
1.5(5) + 2.25(3) = 14.25
• 6 necklaces and no bracelets •
1.5(0) + 2.25(6) = 13.5
No necklaces and 8 bracelets
1.5(8) + 2.25(0) = 12
Amount charged per Tshirt = c
Setup fee = $40
Number of students in drama club = 21
Total cost of order = $187
Calculate C ;
Total order cost = set up fee + (cost per shirt * number of shirts)
Total order cost = 40 + 21c
187 = 40 + 21c
187 - 40 = 21c
147 = 21c
c = 147 / 21
C = 7
Hence cost per shirt = $7
Answer:
Keenan's z-score was of 0.61.
Rachel's z-score was of 0.81.
Step-by-step explanation:
Z-score:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points.
This means that 
So



Keenan's z-score was of 0.61.
Rachel scored 78 points on an exam that had a mean score of 75 points and a standard deviation of 3.7 points.
This means that
. So



Rachel's z-score was of 0.81.
Answer:
distribute bud
Step-by-step explanation:
distribute throught the parethesis first
Answer:
7/10
Step-by-step explanation: