f(x)g(x) = 9x² + 10x - 16
<u>Step-by-step explanation:</u>
Step 1:
Given f(x) = 3x - 4 × 2 + 6x and g(x) = 5x + 2 × 2 - 3x
f(x) = 9x - 8
g(x) = 2x + 4
f(x)g(x) = (9x - 8)(2x + 4)
= 18x² + 36x - 16x -32
= 18x² + 20x - 32
= 9x² + 10x - 16
Answer:
c
Step-by-step explanation:
i think c but not sure
The radius of a circle is a=pi r^2.
so 360.9=3.14r^2, so that's around 114.94=r^2
r=10.72
The standard form of the equation of a circle of radius r, with (assuming centre h, k) is given as:
(X-h)^2 + (y-k)^2 = r^2
As we are required to write an equation in standard form for the circle with radius 9 centred at the origin.
Centre(h,k)=(0,0), r=9
Substituting these values into the standard form of the equation of a circle given above:
(X-0)^2 + (y-0)^2 = 9^2
X^2 + y^2 =81
The standard form is x^2 + y^2 =81
I’m pretty sure this is right
Answer:
d: 4 r:5
Step-by-step explanation:
for domain the x coordinates doesn't go over -2 on the left or 2 on the right so if u add the units of the space in between it's 4 since 2- (-2)=4
for the range, the y coordinates never goes over 3 or -2 so range is 5 is u add the units in between
I hope that makes sense!
