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satela [25.4K]
3 years ago
12

Which equation can be used to find 40 percent of 25?

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
7 0

Answer:

Step-by-step explanation:

40%=0.4

0.4*25=10

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The population of a city (in millions) at time t (in years) is P(t)=2.6 e 0.005t , where t=0 is the year 2000. When will the pop
lora16 [44]

Answer:

  year 2139

Step-by-step explanation:

The population will double when the factor e^(.005t) is 2.

  e^(.005t) = 2

  .005t = ln(2)

  t = ln(2)/0.005 = 138.6

The population will be double its size at t=0 when t=138.6. That is the population will be about 5.2 million in the year 2139.

7 0
3 years ago
A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
In △QRS, QR ‖ TU. Given that TQ=6, ST=10, and UR=15, find SU.
tresset_1 [31]

Answer:

SU=25

Step-by-step explanation:

We can set up a ratio as STU and SQR are similar because of the SAS similarity theorem.

TQ:SQ

SQ=ST+TQ=10+6=16

6:16=3:8

Therefore the ratio of STU:SQR is 3:8

We can use this to find SU

UR:SR=3:8

15:SR=3:8

Cross multiply

3SR=120

SR=40

SU=SR-UR

SU=40-15

SU=25

8 0
3 years ago
I need help on this question
Pie

Answer:

(f-g)(4) = 10

Step-by-step explanation:

(f-g)(x) = f(x) - g(x)

= 1/2 x^2 - 1/4 x + 4 - 1/2 x + 1

= 1/2 x^2 - 1/4 x - 1/2 x + 4 + 1

= 1/2 x^2 - 3/4 x + 5

(f-g)(4)

= 1/2 (4)^2 - 3/4 (4) + 5

= 1/2 * 16 - 3 + 5

= 8 - 3 + 5

= 5 + 5

= 10

4 0
2 years ago
Sentence represents this repeated additio<br> 6 + 6 + 6 =
yawa3891 [41]
This can also be represented as 6x3. I hope that helped
7 0
3 years ago
Read 2 more answers
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