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sineoko [7]
3 years ago
12

HeLP pLEase omg Im finally finishing

Biology
2 answers:
suter [353]3 years ago
4 0
Scavenger
Since vultures are scavengers, their family have to be so too.
kicyunya [14]3 years ago
4 0

IT would be scavenger or at least it should be lol.

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What is the thin layer of endothelial tissue that lines the inner surface of the heart and the valves called
serious [3.7K]

Answer:

Endocardium

Explanation:

The endocardium makes the innermost lining of the wall of the heart. It is present over the thin layer of connective tissue. The function of the endocardium is to provide a smooth lining for the chambers of the heart. The valves present in the heart also have endocardium. The dense connective tissue of the heart valves is covered by endocardium.

The presence of the smooth endocardium made up of endothelium reduces the surface friction as blood passes through the heart. The endocardium of heart chambers is continuous with the endothelial lining of the large blood vessels that are attached to the heart.

8 0
3 years ago
The immunoglobulin light chain does not have a D segment. In humans, there are two different possible light chain proteins, term
wlad13 [49]

Answer:

295  

Explanation:

Antibodies (also known as immunoglobulins) are immune system-related proteins that circulate in the bloodstream in order to recognize pathogenic harmful substances (antigens) and neutralize them. An antibody consists of two immunoglobulin heavy chains and two immunoglobulin light chains. There are two types of immunoglobulin light chains: 1-the kappa (κ) light chain, which is encoded by the immunoglobulin κ locus; and 2-the lambda (λ) light chain, which is encoded by the immunoglobulin λ locus. The immunoglobulin light chain is a multidomain protein composed of two domains: 1- the N-terminal variable (V) domain and 2-the C-terminal constant (C) domain. V(D)J recombination is a type of somatic rearrangement process by which T and B cells can assemble different gene segments, which are referred to as variable (V), diversity (D) and joining (J) gene segments. In the question above the number of possible genomic recombination events between immunoglobulin gene segments can be calculated as >> (5 x 35) + (4 x 30) = 295.

4 0
2 years ago
NEED YOUR HELP!!! BRAINLY
SSSSS [86.1K]

Answer: Your answer is B

Explanation: Because unicellular organism are very simple organisms such as bacteria.

3 0
3 years ago
Free Points and brainiest answer. The answer can be whatever. I'm deleting my account so I thought I would just hand out the poi
OLEGan [10]

Answer:

Is this legit? Cause if so I yaaaaayyyyyyy!!!! thank sssssss

3 0
3 years ago
Read 2 more answers
In fruit flies, gray bodies (G) are dominant over black bodies (g), and red eyes (R) are dominant over orange eyes (r). Each ind
Sindrei [870]

Answer:

The predicted genotype of the offspring is GgRr.

Explanation:

The gray body is dominant over black body. The genotype of gray body is GG and the genotype of black body is gg. Red eyes are dominant over orange eyes. The genotype for red eye is RR whereas the genotype of orange eye is rr.

GGRR is crossed with ggrr, the offspring produced by this cross is GgRr with gray body and red eyes.

GGRR  ×   ggrr

 GgRr.

4 0
2 years ago
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