Considering the following;
I. Heat is not readily available to all living cells.
II. Heat at excessive amounts denatures proteins.
III. Heat does not provide the activation energy for their reactions.
IV. When a critical temperature is reached, proteins no longer function
Answer;
I and IV
Explanation;
Living cells cannot use heat to provide the activation energy for biochemical reactions because heat is not readily available to all living cells and also when a critical temperature is reached, proteins no longer function.
Too much heat can kill an organism by rendering its organelles, cells, tissues and organs permanently inoperable and un-salvageable. The same process can be observed in tissues at low temperatures, and is the cause of frostbite. This is because enzymes are denatured by high temperature and inactivated by low.
C It controls what is allowed to enter or leave the cell.
Nottingham.ac.uk will help you with that question:)
Answer:
The fate of glucose-6-phosphate,glycolytic intermediates and pentose phosphate pathways are described below
Explanation:
Fate of Glucose -6-phosphate
Glucose-6-phosphate undergo dephosphorylation to form glucose when there is an increase demand of glucose in the body.
Glucose-6-phosphate enters into pentose phosphate pathway to synthesize ribose-5-phosphate which is used during denovo pathway of purine nucleotide biosynthesis.
Fate of glycolytic intermediates
Glyceraldehyde-3-phosphate is an important intermediate of glycolysis.The glyceraldehyde-3-phosphate act as a precursor during lipogenesis that deals with the biosynthesis of triacylglycerol.
Fate of pentose phosphate pathway intermediates
Ribose-5-phosphate and NADPH are the important intermediates of pentone phosphate pathway.
Ribose-5-phosphate act as a substrate molecule during the denovo biosynthesis pathway of purine nucleotides.
NADPH act as a reducing agent during fatty acid biosynthesis process.
