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dimaraw [331]
3 years ago
7

What Is 2(2x-5)=3x+x-2x ?

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
7 0

Answer:

x = 5

Step-by-step explanation:

Solve for x:

2 (2 x - 5) = 3 x + x - 2 x

3 x + x - 2 x = 2 x:

2 (2 x - 5) = 2 x

Divide both sides by 2:

2 x - 5 = x

Subtract x from both sides:

(2 x - x) - 5 = x - x

2 x - x = x:

x - 5 = x - x

x - x = 0:

x - 5 = 0

Add 5 to both sides:

x + (5 - 5) = 5

5 - 5 = 0:

Answer: x = 5

Aleonysh [2.5K]3 years ago
6 0
2(2x-5)=3x+x-2x
4x-10=2x
4x-2x=10
2x=10
x=10/2
x=5

explanation: if 2(2) its mean 2x2
then you should do the class that the algebra at the left and the number at the right example(3x=9)
after that , divide the single number (9) by the algebra number (3) —(9/3)
so the answer will be the value of x
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Bingel [31]

To solve for the given problem above:

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3 years ago
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In a simple random sample of 14001400 young​ people, 9090​% had earned a high school diploma. Complete parts a through d below.
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Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has ​increased.

Step-by-step explanation:

Let <em>p</em> = proportion of young people who had earned a high school diploma.

A sample of <em>n</em> = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

\hat p=0.90

(a)

The standard error for the estimate of the percentage of all young people who earned a high school​ diploma is given by:

SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

Compute the standard error value as follows:

SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

       =\sqrt{\frac{0.90(1-0.90)}{1400}}\\

       =0.008

Thus, the standard error for the estimate of the percentage of all young people who earned a high school​ diploma is 0.0080.

(b)

The margin of error for (1 - <em>α</em>)% confidence interval for population proportion is:

MOE=z_{\alpha/2}\times SE_{\hat p}

Compute the critical value of <em>z</em> for 95% confidence level as follows:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the margin of error as follows:

MOE=z_{\alpha/2}\times SE_{\hat p}

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Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has​ increased, the hypothesis is defined as:

<em>H₀</em>: The percentage of young people who earn high school diplomas has not​ increased, i.e. <em>p</em> = 0.80.

<em>Hₐ</em>: The percentage of young people who earn high school diplomas has not​ increased, i.e. <em>p</em> > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of <em>p</em>, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has ​increased.

8 0
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Answer:

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Answer:

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