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diamong [38]
3 years ago
12

I need these answer ASAP PLEASE!!!!

Mathematics
1 answer:
Archy [21]3 years ago
7 0

Answer:x=150 y=30

Step-by-step explanation:

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Arthur bought a life insurance policy at $10.98 per month for a 20 year term. What will he pay over 20 years for the premium?
andre [41]
12(months) x 20 (years) = 240

10.98 x 240 = 2635.20

So Arthur will pay $2635.20 over 20 years for premium.

I hope this helps :)
5 0
2 years ago
Read 2 more answers
What is (6x+4) - (4x+2)
Nana76 [90]

Answer:

x = -1

Step-by-step explanation:

1. Simplifying

6x + 4 = 4x + 2

2. Reorder the terms

4 + 6x = 4x + 2 to 4 + 6x = 2 + 4x

3. Solving

4 + 6x = 2 + 4x

4. Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right. Then add '-4x' to each side of the equation.

4 + 6x + -4x = 2 + 4x + -4x

5. Combine like terms: 6x + -4x = 2x

4 + 2x = 2 + 4x + -4x

6. Combine like terms: 4x + -4x = 0

4 + 2x = 2 + 0

4 + 2x = 2

7. Add '-4' to each side of the equation.

4 + -4 + 2x = 2 + -4

8. Combine like terms: 4 + -4 = 0

0 + 2x = 2 + -4

2x = 2 + -4

9. Combine like terms: 2 + -4 = -2

2x = -2

10. Divide each side by '2'.

x = -1

11. Simplifying

x = -1

4 0
3 years ago
What is the value of x?
Mazyrski [523]

x/20 = 21/14 (similar proportions)

x/20 = 3/2 (simplify by canceling out a factor of 7)

x = 30

6 0
3 years ago
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Write the words for:<br><br> (3/4 - 1/5) x 4:
adoni [48]

Answer:

three-forth minus one-fifth times four

Step-by-step explanation:

3 0
3 years ago
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Calculate two iterations of Newton's Method to approximate a zero of the function using the given initial guess. (Round your ans
VikaD [51]

Answer:

The two iterations of f(x) = 1.5598

Step-by-step explanation:

If we apply  Newton's iterations method, we get a new guess of a zero of a function, f(x), xₙ₊₁, using a previous guess of, xₙ.

xₙ₊₁ = xₙ - f(xₙ) / f'(xₙ)

Given;

f(xₙ) = cos x, then  f'(xₙ) = - sin x

cos x / - sin x = -cot x

substitute in "-cot x" into the equation

xₙ₊₁ = xₙ - (- cot x)

xₙ₊₁ = xₙ + cot x

x₁ = 0.7

first iteration

x₂ = 0.7 + cot (0.7)

x₂ =  0.7 + 1.18724

x₂ = 1.88724

 

second iteration

x₃ = 1.88724 + cot (1.88724)

x₃ = 1.88724 - 0.32744

x₃ = 1.5598

To four decimal places = 1.5598

4 0
3 years ago
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