Answer:
y=3/2x+1
Step-by-step explanation:
y-4= -⅔(x-6)
y-4=-⅔x+4
y=-⅔x+4+4
(equation of line 1) y= -⅔x+8 gradient= -⅔
(line 2)gradient=3/2
note* the gradients of perpendicular lines multiplied result to -1
gradient=<u>y²-y²</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>x²-x¹
<u>3</u><u> </u>=<u>y</u><u>+</u><u>2</u>
<u> </u><u> </u>2. x+2
multiply both sides by 2(x+2)to remove the denominators
3(x+2)=2(y+2)
3x+6=2y+4
3x+6-4=2y
3x+2=2y
divide all sides by 2
3/2x+1=y
y=3/2x+1
The way you find area is multiplying width times height, so you have to multiply 15 by 4 which equals 60. Therefore the answer is 60
Answer:
0 or 0/6
Step-by-step explanation:
3+6=9
-2+0=-2
0/6=0
Answer:
35°
Step-by-step explanation:
We assume that points S, T, U, V all lie on the circle.
Inscribed angle TUV intercepts long arc VST and short arc VUT. The long arc has measure 220°, so the measure of the short arc is 360° -220° = 140°.
Since chords UV and UT are the same length, point U bisects arc VUT. That means the measure of arc VU is 140°/2 = 70°.
Inscribed angle VSU intercepts arc VU, so has half the measure of the arc:
∠VSU = 70°/2
∠VSU = 35°
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B. Parallel faces
Not all sides need to be parallel and a polygon has only 1 face unless cut
