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I am Lyosha [343]
2 years ago
10

*math please help* Simplify.

Mathematics
2 answers:
Ghella [55]2 years ago
3 0

Given : \frac{\frac{4x}{5 + x}}{\frac{6x}{x + 2}}

\implies \frac{4x}{5 + x}\times\frac{x + 2}{6x}

\implies \frac{2}{x + 5}\times\frac{x + 2}{3}

\implies \frac{2(x + 2)}{3(x + 5)}

\implies \frac{2x + 4}{3x + 15}

amm18122 years ago
3 0
\frac{ \frac{4x}{5 + x} }{ \frac{6x}{x + 2} } \\ = \frac{4x}{5 + x } ( \frac{x + 2}{6x} )
= \frac{4x^{2} + 8x}{30x + {6x}^{2} } \\ = \frac{2x(2 {x} + 4) }{2x(3 {x}+ 15)} \\ = \frac{2 {x} + 4 }{3 {x} + 15}
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KATRIN_1 [288]
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6 0
1 year ago
Polynomial function in standard form with zeros 5,-4,1
Oksanka [162]

Answer:

\boxed{\sf \ \ \  x^3-2x^2-19x+20 \ \ \  }

Step-by-step explanation:

hello,

by definition we can write

(x-5)(x+4)(x-1)

as 5,-4,1 are the zeroes

now we have to write it in the standard form, let's do it

(x-5)(x+4)(x-1)=(x^2+4x-5x-20)(x-1)\\=(x^2-x-20)(x-1)=x^3-x^2-20x-x^2+x+20\\=x^3-2x^2-19x+20

hope this helps

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