Answer:
We can have two cases.
A quadratic function where the leading coefficient is larger than zero, in this case the arms of the graph will open up, and it will continue forever, so the maximum in this case is infinite.
A quadratic function where the leading coefficient is negative. In this case the arms of the graph will open down, then the maximum of the quadratic function coincides with the vertex of the function.
Where for a generic function:
y(x) = a*x^2 + b*x + c
The vertex is at:
x = -a/2b
and the maximum value is:
y(-a/2b)
terms is x first then terms in y and constant after the equals
Its C
Answer:
NO
Step-by-step explanation:
Note :
Consider a triangle with sides‘s length a , b and c
triangle inequalities state that we must have c - a < b < c + a
now , is the third side always the longest ?
the answer is NO: (let’s take a counter example )
in a triangle with 2 sides‘s length 3 , 4
the third side could measure 2
because 4-3 < 2 < 4+3
Let b>a,
a+b=40 so we can say a=40-b
We are told that b-a=6.5, using a found above in the equation gives us:
b-(40-b)=6.5
b-40+b=6.5
2b-40=6.5
2b=46.5
b=23.25, and since a=40-b
a=40-23.25
a=16.75
So a=16.75 and b=23.25
check...
16.75+23.25=40, 40=40
23.25-16.75=6.5, 6.5=6.5
