ABCD is a rhombus with diagonals intersecting at E. If mABC is three times mBAD, find mABC.

An animal shelter spends $1.00 per day to care for each cat and $4.50 per day to care for each dog. Damian noticed that the shel

Amanda [17]

Answer:

4 cats

18 dogs

18 x 4.5 = 81

4 x 1.0 = 4

81 + 4 = 85.00

22 ÷ 2 = 11

Start there and just numbers and cost till you find the right numbers

Step-by-step explanation:

7 0

3 years ago

Find the quotient 1 5 ÷ 3 4 = _____

zavuch27 [327]

Answer:

15/34=0.44117647058823529411764705882353‬

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If f(x)= 4-2x and g(x)=6x which expression is equivalent to (g-f)(3)

Dmitrij [34]

Answer:

(g-f)(3) = 20

Step-by-step explanation:

g(3)=6 * (3) = 18

f(3)= 4-2(3) = 4 - 6 = -2

So

(g-f)(3) = 18 - (-2) = 20

4 0

3 years ago

The following are the ages of 13 history teachers in a school district. 24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56 Notic

pishuonlain [190]

The five-number summary and the interquartile range for the data set are given as follows:

Minimum: 24.

Lower quartile: 29.

Median: 43.

Upper quartile: 50.

Maximum: 56.

Interquartile range: 50 - 29 = 21.

<h3>What are the median and the quartiles of a data-set?</h3>

The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.

The first quartile is the median of the first half of the data-set.

The third quartile is the median of the second half of the data-set.

The interquartile range is the difference between the third quartile and the first quartile.

In this problem, we have that:

The minimum value is the smallest value, of 24.

The maximum value is the smallest value, of 56.

Since the data-set has odd cardinality, the median is the middle element, that is, the 7th element, as (13 + 1)/2 = 7, hence the median is of 43.

The first quartile is the median of the six elements of the first half, that is, the mean of the third and fourth elements, mean of 29 and 29, hence 29.

The third quartile is the median of the six elements of the second half, that is, the mean of the third and fourth elements of the second half, mean of 49 and 51, hence 50.

The interquartile range is of 50 - 29 = 21.

More can be learned about five number summaries at brainly.com/question/17110151

#SPJ1

3 0

2 years ago

The head of maintenance at XYZ Rent-A-Car believes that the mean number of miles between services is 3639 3639 miles, with a var

Andrei [34K]

Answer:

96.6% probability that the mean of a sample would differ from the population mean by less than 126 miles

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

A reminder is that the standard deviation is the square root of the variance.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

$\mu = 3639, \sigma = \sqrt{145161} = 381, n = 41, s = \frac{381}{\sqrt{41}} = 59.5$

Probability that the mean of the sample would differ from the population mean by less than 126 miles

This is the pvalue of Z when X = 3639 + 126 = 3765 subtracted by the pvalue of Z when X = 3639 - 126 = 3513. So

X = 3765

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{3765 - 3639}{59.5}$

$Z = 2.12$

$Z = 2.12$ has a pvalue of 0.983

X = 3513

$Z = \frac{X - \mu}{s}$

$Z = \frac{3513 - 3639}{59.5}$

$Z = -2.12$

$Z = -2.12$ has a pvalue of 0.017

0.983 - 0.017 = 0.966

96.6% probability that the mean of a sample would differ from the population mean by less than 126 miles

3 0

3 years ago