Question

PLZ HELP WORTH 25 PTS!!!!!

Answer 1

Answer:

$\displaystyle y=- \frac{1}{2}x-3$

(first option)

Step-by-step explanation:

Linear Functions

They can be defined by knowing two points on them or a point and the slope of the line. The portion "a" of the piecewise function must have these conditions, only by looking at the graph

* It must be decreasing, the slope must be negative

* It must be defined for x<-2, because for x>-2, the function is defined by another piece.

* It must pass through the point (-2,-2)

Options 2 and 4 are immediately discarded, since x>2

Testing it (-2,-2) belongs to

$\displaystyle y=- \frac{1}{2}x-3$

$\displaystyle y=- \frac{1}{2}(-2)-3=1-3=-2$

The point (-2,-2) belongs to this function, so it's the correct choice. Let's verify the last function

$\displaystyle y=- \frac{1}{2}x-6$

$\displaystyle y=- \frac{1}{2}(-2)-6=-5$

This is not the point we are testing, so the portion of the graph labeled "a" is

$\boxed{\displaystyle y=- \frac{1}{2}x-3}$

(First option)