Answer: Please see below for answers
Explanation: Matching appropriate labels , we have
1)3/4 of the way to second equivalence point of a diprotic acid/strong base titration-- pH=pka₂
equivalence point of a weak base/strong acid titration=pH<7
equivalence point of a strong acid/strong base titration= pH=7
equivalence point of a weak acid/strong base titration=pH>7
half-way to equivalence point of a weak acid/strong base titration pH =pka
where
pH gives the measure of the amount of concentration of hydrogen ions in an aqueous solution.
pKa is known as acid dissociation constant which explains the equilibrum at which a chemical species can give out or receive proton
pka₂ is the acid dissociation constant for the second ionization energy.
Answer:
Here's what I get.
Explanation:
Your unbalanced nuclear equation is:

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.
Then
95 = x + 2, so x = 95 - 2 = 93
243 = y + 4, so y = 243 - 4 = 239
Element 93 is neptunium, so the nuclear equation becomes
The answer is Heyyy friend in know because I took the test
Answer:

Explanation:
The relation between Kp and Kc is given below:
Where,
Kp is the pressure equilibrium constant
Kc is the molar equilibrium constant
R is gas constant
T is the temperature in Kelvins
Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)
For the first equilibrium reaction:
Given: Kc = 0.50
Temperature = ![400^oC=[400+273]K=673K](https://tex.z-dn.net/?f=400%5EoC%3D%5B400%2B273%5DK%3D673K)
R = 0.082057 L atm.mol⁻¹K⁻¹
Δn = (2)-(3+1) = -2
Thus, Kp is:
