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Ber [7]
3 years ago
8

8. Based on the formula, predict whether each of the following compounds is primarily ionic or primarily covalent. a. sodium iod

ide (NaI) d. ammonia (NH3) b. methane (CH4) e. glucose (C6H12O6) c. calcium chloride (CaCl2)
Chemistry
1 answer:
Lina20 [59]3 years ago
8 0

primarily ionic  include = sodium iodide( NaI) ,   calcium chloride  ( CaCl2)


primarily covalent    include  - Ammonia (NH3) , Methane ( CH4)  and  

                                                   Glucose  (C6H12O6)


Explanation

ionic  bond  is formed  when  there is complete transfer of electron between atoms. It occur  between metal  which  donate electrons and  a  non  metal which accept  electrons.

 for  example  in  formation  of CaCl2,   ca  donate  2 electron to 2  Cl atom, while  2 Cl atom accept the 2  electrons  to form ionic bond.

 Covalent bond  is formed  when two or  more  non  metal  form bond by sharing  electrons pairs.

For  example in NH3   3 pairs of electron are shared.  to form covalent bond.

                               

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Match the following.
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Answer: Please see below for answers

Explanation: Matching appropriate labels , we have

1)3/4 of the way to second equivalence point of a diprotic acid/strong base titration-- pH=pka₂

equivalence point of a weak base/strong acid titration=pH<7

equivalence point of a strong acid/strong base titration= pH=7

equivalence point of a weak acid/strong base titration=pH>7

half-way to equivalence point of a weak acid/strong base titration pH =pka

where

pH gives the measure of the amount of concentration of hydrogen ions in an aqueous solution.

pKa  is known as acid dissociation constant which explains the equilibrum at which a chemical species can give out or receive proton

pka₂ is the acid dissociation constant for the second ionization energy.

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Write the nuclear equation to describe the alpha decay of 243 95 Am
motikmotik

Answer:

Here's what I get.

Explanation:

Your unbalanced nuclear equation is:

_{95}^{243}\text{Am} \longrightarrow \, _{x}^{y}\text{Z} +\, _{2}^{4}\text{He}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

  95 = x + 2, so x =   95 - 2 =    93

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Element 93 is neptunium, so the nuclear equation becomes

_{95}^{243}\text{Am} \longrightarrow \, _{93}^{239}\text{Np} + \, _{2}^{4}\text{He}  

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onvert the value of Kc to a value of Kp for the following reaction: N2(g)+3H2(g)⇌2NH3(g) Kc = 0.50 at 400 °C.
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Answer:

K_p= 0.00016

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

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T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

N_2_{(g)}+3H_2_{(g)}\rightleftharpoons2NH_3_{(g)}

Given: Kc = 0.50

Temperature = 400^oC=[400+273]K=673K

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (2)-(3+1) = -2

Thus, Kp is:

K_p= 0.50\times (0.082057\times 673)^{-2}

K_p= 0.00016

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