1*10^9 molecules* (1 mol/ (6.02*10^23 molecules))= 2*10^(-15) mol.
The final answer is 2*10^(-15) mol O2~
Explanation:
to calculate theoratical yield...first we must calculate how much Sucrose moles we have..in order to to do so...we must calculate molar mass of sucrose.
molar mass of sucrose is 342.3 g/mol.
now we can calculate how many sucrose moles we have by dividing the mass with molar mass of sucrose
735g/(342.3g/mol)=2.147mol
theoratically...according to stoichiometry..every 1 mole of sucrose yields 4 moles of ethanol...so...
2.147mole yield 2.147*4mol=8.588mol
now we must calculate weight of that much ethanol..molar mass of ethanol is 46.07 g/mol...
so we can multiple moles by molar mass to obtain the weight 8.588mol*46.07g/mol=395.649g
but we only obtained 310.5g...so percentage we have is

78.47%
if there is trouble with molar mases I used....use what you calculated...
If my explanation is good enough...please mark it as brainliest.thanks
Answer:
The answer is 30 g of sodium hydrocarbonate
Explanation:
This is a acid-base reaction, so in order to neutralise the spilled acid, the mol of spilled acid should be calculated.
M = n / V => n = M x V = 0.028 x 6.2 = 0.1736 mol
Since 1 mol of sulfuric acid generates 2 mol of H⁺, so the mole of H⁺ is 0.3472 mol or 0.35 mol with two significant figures.
To neutralized the acid, we need at least the same mole of base, so we need at least 0.35 mol of NaHCO₃, which can be converted to its mass at 29.4 g.
Since the answer need to be expressed in two significant figures and also need to make sure to neutralize all the acid, so we will use a little excess base. The answer is 30 g.