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Damm [24]
3 years ago
9

Vera is using her phone.Its battery life is down to 2/5,and it drains another 1/9 every other. How many hours will her battery l

ast
Mathematics
2 answers:
Novosadov [1.4K]3 years ago
7 0

Answer:

18/5 HOURS

Step-by-step explanation:

Margarita [4]3 years ago
3 0

Let x be total hours of battery life. We have been given that battery life of Vera's phone is down to 2/5. So remaining battery life,

1-\frac{2}{5}=\frac{5-2}{5}=\frac{3}{5}

We have been also given that it drains another 1/9 every other hour. Now let us substitute our given information into an equation.

\frac{1}{9}\cdot x=\frac{3}{5}

Now we will solve for x.

x=\frac{3\cdot 9}{5}=\frac{27}{5}

x=(5+\frac{2}{5})hours

Let us convert 2/5 into minutes. We know 1 hour has 60 minutes.

60\cdot \frac{2}{5}=24\text{minutes}

Therefore, remaining battery life will be 5 hours and 24 minutes.



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The length of a quarter is 0.953 inch. round the length of a quarter to the nearest tenth of an inch
liraira [26]

Answer:

1 inch

Step-by-step explanation:

The 9 is in the tenths place so you look to the hundredths place and if the number is greater than or equal to 5 then the 9 can round up.

The hundredths place is 5 so the 9 rounds up and since it can not round up in the tenths place you put the rounding in the front so the answer is 1 inch.

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3 years ago
First five common multiples of 7and 20
gulaghasi [49]
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3 years ago
What are the coordinates of the point on the directedline segment from K(-5,-4) to L(5,1) that partitionsthe segment into a rati
Diano4ka-milaya [45]
You can solve this either just plain algebra or with the use of trigonometry.
In this case, we'll just use algebra.
 
So, if we let M be the the point that partitions the segment into a ratio of 3:2, we have this relation:
KM/ML = 3/2
KM = 1.5 ML

We also have this:
KL = KM + ML
Substituting KM,
KL = (3/2) ML + ML
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Using the distance formula and the given coordinates of the K and L, we get the length of KL
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Since,
KL = 2.5 ML

Substituting KL,
ML = (1/2.5) KL = (1/2.5) 5 sqrt(5) = 2 sqrt(5)

Using again the distance formula from M to L and letting (x,y) as the coordinates of the point M
ML = 2 sqrt(5) = sqrt ( (5-x)^2 + (1-y)^2 )   [let this be equation 1]

In order to solve this, we need to find an expression of y in terms of x. We can use the equation of the line KL.
The slope m is:
m = (1-(-4))/(5-(-5) = 0.5

Using the general form of the linear equation:
y = mx +b
We substitue m and the coordinate of K or L. We'll just use K.
-5 = (0.5)(-4) + b
b = -1.5

So equation of the line is
y = 0.5x - 1.5      [let this be equation 2]

Substitute equation 2 to equation 1 and solving for x, we get 2 values of x,
x=1, x=9

Since 9 does not make sense (it does not lie on the line), we choose x=1.
Using the equation of the line, we get y which is -1.

So, we get the coordinates of point M which is (1,-1)
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Answer:

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