Make them all have the same denominator
32
25+12 16/32+488/32+124/32+38/32+25/32
Add all of the numerators... to get 691/32+1184/32
1875/32
Simplify to get 58 19/32
Step-by-step explanation:
the third of 7 consecutive numbers is 12.
so, this looks like
..., ..., 12, ..., ..., ..., ...
that means the numbers have to be
10, 11, 12, 13, 14, 15, 16
the sum is then
16+10 + 15+11 + 14+12 + 13 = 3×26 + 13 = 91
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